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How to encode Realm's List<> type

Tags:

swift

realm

I am trying to encode my Realm database to JSON. Everything is working except the List<> encoding. So my question is, how would you encode List<>? Because the List doesn't conform to Encodable neighter Decodable protocol.

Right now I am doing this:

@objcMembers class User: Object, Codable{
    dynamic var name: String = ""
    let dogs = List<Dog>()


    private enum UserCodingKeys: String, CodingKey {
        case name
        case dogs
    }

    convenience init(name: String) {
        self.init()
        self.name = name
    }

    func encode(to encoder: Encoder) throws {
        var container = encoder.container(keyedBy: UserCodingKeys.self)
        try container.encode(name, forKey: .name)

    }



@objcMembers class Dog: Object, Codable{
    dynamic var name: String = ""
    dynamic var user: User? = nil

    private enum DogCodingKeys: String, CodingKey {
        case name
    }

    convenience init(name: String) {
        self.init()
        name = name
    }

    func encode(to encoder: Encoder) throws {
        var container = encoder.container(keyedBy: DogCodingKeys.self)
        try container.encode(name, forKey: .name)

    }
}

and like this I am trying to do it:

var json: Any?
let user = RealmService.shared.getUsers()
var usersArray = [User]()
for user in users{
     usersArray.append(user)
}

let jsonEncoder = JSONEncoder()
let jsonDecoder = JSONDecoder()
let encodedJson = try? jsonEncoder.encode(portfoliosArray)


        if let data = encodedJson {
            json = try? JSONSerialization.jsonObject(with: data, options: .allowFragments)
            if let json = json {
                print(String(describing: json))
            }
        }

So the question is how I am able to encode the List<Dog>?

like image 509
Tarvo Mäesepp Avatar asked May 24 '26 09:05

Tarvo Mäesepp


1 Answers

To make a Realm object model class with a property of type List conform to Encodable, you can simply convert the List to an Array in the encode(to:) method, which can be encoded automatically.

extension User: Encodable {
    func encode(to encoder: Encoder) throws {
        var container = encoder.container(keyedBy: CodingKeys.self)
        try container.encode(self.username, forKey: .username)
        let dogsArray = Array(self.dogs)
        try container.encode(dogsArray, forKey: .dogs)
    }
}

Test classes I used (slightly different from the ones in your question, but I already had these on hand and the methods in question will be almost identical regardless of the variable names):

class Dog: Object,Codable {
    @objc dynamic var id:Int = 0
    @objc dynamic var name:String = ""
}

class User: Object, Decodable {
    @objc dynamic var id:Int = 0
    @objc dynamic var username:String = ""
    @objc dynamic var email:String = ""
    let dogs = List<Dog>()

    private enum CodingKeys: String, CodingKey {
        case id, username, email, dogs
    }

    required convenience init(from decoder: Decoder) throws {
        self.init()
        let container = try decoder.container(keyedBy: CodingKeys.self)
        id = try container.decode(Int.self, forKey: .id)
        username = try container.decode(String.self, forKey: .username)
        email = try container.decode(String.self, forKey: .email)
        let dogsArray = try container.decode([Dog].self, forKey: .dogs)
        dogs.append(objectsIn: dogsArray)
    }
}

Test the encoding/decoding:

let userJSON = """
{
    "id":1,
    "username":"John",
    "email":"[email protected]",
    "dogs":[
        {"id":2,"name":"King"},
        {"id":3,"name":"Kong"}
    ]
}
"""

do {
    let decodedUser = try JSONDecoder().decode(User.self, from: userJSON.data(using: .utf8)!)
    let encodedUser = try JSONEncoder().encode(decodedUser)
    print(String(data: encodedUser, encoding: .utf8)!)
} catch {
    print(error)
}

Output:

{"username":"John","dogs":[{"id":2,"name":"King"},{"id":3,"name":"Kong"}]}

like image 81
Dávid Pásztor Avatar answered May 27 '26 17:05

Dávid Pásztor



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