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I have the following code written in python 2.7
# -*- coding: utf-8 -*-
import sys
_string = "años luz detrás"
print _string.encode("utf-8")
this throws the following error:
print _string.encode("utf-8")
UnicodeDecodeError: 'ascii' codec can't decode byte 0xc3 in position 1: ordinal not in range(128)
Any help appreciated, thanks in advance
626
decode() is a method specified in Strings in Python 2. This method is used to convert from one encoding scheme, in which argument string is encoded to the desired encoding scheme. This works opposite to the encode. It accepts the encoding of the encoding string to decode it and returns the original string.
Python String encode() MethodThe encode() method encodes the string, using the specified encoding. If no encoding is specified, UTF-8 will be used.
The latin-1 encoding in Python implements ISO_8859-1:1987 which maps all possible byte values to the first 256 Unicode code points, and thus ensures decoding errors will never occur regardless of the configured error handler.
UTF-8 is a variable-length encoding, so I'll assume you really meant "Unicode code point". Use chr() to convert the character code to a character, decode it, and use ord() to get the code point. In Python 2, chr only supports ASCII, so only numbers in the [0.. 255] range.
Add u before the "
>>> _string = u"años luz detrás"
>>> print _string.encode("utf-8")
años luz detrás
This would do.
91
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