How to enable front camera in webview for android

Question

How do you enable the front camera on a Webview? I have enable the features in AndroidManifest.xml

 <uses-feature android:name="android.hardware.camera" android:required="true" />
 <uses-feature android:name="android.hardware.camera.front" android:required="true" />

The camera is not going to be used for taking photos or recording, just to switch on the front camera.

When I go to the website using the phone browser the phone camera works once allow the prompt message. How can this work with a webview?

In the html file has a Canvas and Video tag that displays webcam It doesn't record or take pictures it just shows you the camera view.

Here is the html code

 <canvas id="inCanvas"  width="500" height="500" style="display:none"></canvas>
 <video id="inputVideo" width="100" height="100" autoplay loop ></video>

It work with webcam but not with webview in android.

Answer 1

I didnt quite understand, but i thing there could one of the following two, what you want.

1) access camera and just show the video on the screen(not capturing image):

html:

  <canvas id='canvas' width='100' height='100'></canvas> 

js:

 var onFailSoHard = function(e)
    {
            console.log('failed',e);
    }

    window.URL = window.URL || window.webkitURL ;
    navigator.getUserMedia = navigator.getUserMedia || navigator.webkitGetUserMedia;

    var video = document.querySelector('video');

    if(navigator.getUserMedia)
    {
        navigator.getUserMedia({video: true},function(stream) {
        video.src = window.URL.createObjectURL(stream);
        },onFailSoHard);
    }


        var canvas = document.getElementById('canvas'); 
    var ctx = canvas.getContext('2d');
setInterval(function(){ 
ctx.drawImage(video,0,0);
     }, 100);

        }  

2) capture image from the camera:

here is the doc for that.

navigator.camera.getPicture(onSuccess, onFail, { quality: 50,
    destinationType: Camera.DestinationType.DATA_URL
});

function onSuccess(imageData) {
    var image = document.getElementById('myImage');
    image.src = "data:image/jpeg;base64," + imageData;
}

function onFail(message) {
    alert('Failed because: ' + message);
}