How to echo out table rows from the db (php)

Question

i want to echo out everything from a particular query. If echo $res I only get one of the strings. If I change the 2nd mysql_result argument I can get the 2nd, 2rd etc but what I want is all of them, echoed out one after the other. How can I turn a mysql result into something I can use?

I tried:

$query="SELECT * FROM MY_TABLE";
$results = mysql_query($query);
$res = mysql_result($results, 0);

while ($res->fetchInto($row)) {
    echo "<form id=\"$row[0]\" name=\"$row[0]\" method=post action=\"\"><td style=\"border-bottom:1px solid black\">$row[0]</td><td style=\"border-bottom:1px solid black\"><input type=hidden name=\"remove\" value=\"$row[0]\"><input type=submit value=Remove></td><tr></form>\n";
}

Answer 1

$sql = "SELECT * FROM MY_TABLE";
$result = mysqli_query($conn, $sql); // First parameter is just return of "mysqli_connect()" function
echo "<br>";
echo "<table border='1'>";
while ($row = mysqli_fetch_assoc($result)) { // Important line !!! Check summary get row on array ..
    echo "<tr>";
    foreach ($row as $field => $value) { // I you want you can right this line like this: foreach($row as $value) {
        echo "<td>" . $value . "</td>"; // I just did not use "htmlspecialchars()" function. 
    }
    echo "</tr>";
}
echo "</table>";

Answer 2

Expanding on the accepted answer:

function mysql_query_or_die($query) {
    $result = mysql_query($query);
    if ($result)
        return $result;
    else {
        $err = mysql_error();
        die("<br>{$query}<br>*** {$err} ***<br>");
    }
}

...
$query = "SELECT * FROM my_table";
$result = mysql_query_or_die($query);
echo("<table>");
$first_row = true;
while ($row = mysql_fetch_assoc($result)) {
    if ($first_row) {
        $first_row = false;
        // Output header row from keys.
        echo '<tr>';
        foreach($row as $key => $field) {
            echo '<th>' . htmlspecialchars($key) . '</th>';
        }
        echo '</tr>';
    }
    echo '<tr>';
    foreach($row as $key => $field) {
        echo '<td>' . htmlspecialchars($field) . '</td>';
    }
    echo '</tr>';
}
echo("</table>");

Benefits:

• Using mysql_fetch_assoc (instead of mysql_fetch_array with no 2nd parameter to specify type), we avoid getting each field twice, once for a numeric index (0, 1, 2, ..), and a second time for the associative key.

• Shows field names as a header row of table.

• Shows how to get both column name ($key) and value ($field) for each field, as iterate over the fields of a row.

• Wrapped in <table> so displays properly.

• (OPTIONAL) dies with display of query string and mysql_error, if query fails.

Example Output:

Id      Name
777     Aardvark
50      Lion
9999    Zebra

Answer 3

Nested loop to display all rows & columns of resulting table:

$rows = mysql_num_rows($result);
$cols = mysql_num_fields($result);
for( $i = 0; $i<$rows; $i++ ) {
   for( $j = 0; $j<$cols; $j++ ) {
     echo mysql_result($result, $i, $j)."<br>";
   }
}

Can be made more complex with data decryption/decoding, error checking & html formatting before display.

Tested in MS Edge & G Chrome, PHP 5.6

Answer 4

$sql = "SELECT * FROM YOUR_TABLE_NAME";
$result = mysqli_query($conn, $sql); // First parameter is just return of "mysqli_connect()" function
echo "<br>";
echo "<table border='1'>";
while ($row = mysqli_fetch_assoc($result)) { // Important line !!!
    echo "<tr>";
    foreach ($row as $field => $value) { // If you want you can right this line like this: foreach($row as $value) {
        echo "<td>" . $value . "</td>"; 
    }
    echo "</tr>";
}
echo "</table>";

In PHP 7.x You should use mysqli functions and most important one in while loop condition use "mysqli_fetch_assoc()" function not "mysqli_fetch_array()" one. If you would use "mysqli_fetch_array()", you will see your results are duplicated. Just try these two and see the difference.