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How to do Rest Authentication with JAX-RS

I am looking for some pointers on how to secure my rest root resource

@Path("/employee")
public class EmployeeResource {

    @GET
    @Produces("text/html")
    public String get(
        @QueryParam("name") String empname,
        @QueryParam("sn") String sn) {

         // Return a data back.
    }
}

I have read post's regarding basic authetication and OAuth, I know the concept but i am looking for ways on how to implement it in code.

Thanks

like image 475
BinCode Avatar asked Nov 08 '10 14:11

BinCode


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1 Answers

Declare an interceptor:

 <bean id="securityInterceptor" class="AuthenticatorInterceptor">
<property name="users">
  <map>
<entry key="someuser" value="somepassword"/>
  </map>
</property>

Then use it:

  <jaxrs:server address="/">
      <jaxrs:inInterceptors>
          <ref bean="securityInterceptor"/>
      </jaxrs:inInterceptors>
      (etc)

Then your AuthenticationInterceptor, along the lines of:

import java.util.Map;

import org.apache.cxf.message.Message;
import org.apache.cxf.phase.PhaseInterceptor;
import org.apache.cxf.phase.AbstractPhaseInterceptor;
import org.apache.cxf.phase.Phase;
import org.apache.cxf.configuration.security.AuthorizationPolicy;
import org.apache.cxf.interceptor.Interceptor;

import org.springframework.beans.factory.annotation.Required;

public class AuthenticatorInterceptor extends AbstractPhaseInterceptor<Message> {

    private Map<String,String> users;

    @Required
    public void setUsers(Map<String, String> users) {
        this.users = users;
    }

    public AuthenticatorInterceptor() {
        super(Phase.RECEIVE);
    }

    public void handleMessage(Message message) {

        AuthorizationPolicy policy = message.get(AuthorizationPolicy.class);

    if (policy == null) {
        System.out.println("User attempted to log in with no credentials");
        throw new RuntimeException("Denied");
        }

    String expectedPassword = users.get(policy.getUserName());
    if (expectedPassword == null || !expectedPassword.equals(policy.getPassword())) {
        throw new RuntimeException("Denied");
    }
    }

}

Defining acceptable credentials in a more convenient way is left as an exercise for the reader.

like image 70
woddle Avatar answered Oct 25 '22 17:10

woddle