How to do group by and take Count of one column divide by count of unique of second column of data frame in python pandas?

Question

I have panda data frame with 4 column say 'col1', 'col2', 'col3' and 'col4' now I want to group by col1 and col2 and want to take aggregate say below.

Count(col3)/(Count(unique col4)) As result_col

How do I do this? I am using MySql with pandas.

I have tried many things from the internet but not getting an exact solution, that's why I am posting here. Give reason of downvote so I can improve my question.

Answer 1

It seems you need aggregate by size and nunique and then div output columns:

df = pd.DataFrame({'col1':[1,1,1],
                   'col2':[4,4,6],
                   'col3':[7,7,9],
                   'col4':[3,3,5]})

print (df)
   col1  col2  col3  col4
0     1     4     7     3
1     1     4     7     3
2     1     6     9     5

df1 = df.groupby(['col1','col2']).agg({'col3':'size','col4':'nunique'})
df1['result_col'] = df1['col3'].div(df1['col4'])
print (df1)
           col4  col3  result_col
col1 col2                        
1    4        1     2         2.0
     6        1     1         1.0