How to do add all with java streams?

Question

How do I do add all with java 8 ?

processeditemList is a Map<Integer, Map<Item, Boolean>> 

As for now I am doing :

List<Item> itemList = Lists.newLinkedList();
for (Map<Item, Boolean> entry : processeditemList.values()) {
    itemList.addAll(entry.keySet());
}
return itemList;

Answer 1

You can use flatMap. It's used to combine multiple streams into a single one. So here you need to create a stream of collections, and then create a stream from each of them:

processeditemList.values().stream()
    .map(Map::keySet)     // Stream<Set<Item>>
    .flatMap(Set::stream) // convert each set to a stream
    .collect(toList());   // convert to list, this will be an ArrayList implmentation by default

If you want to change default List implementation, then you can use below collector:

Collectors.toCollection(LinkedList::new)

LinkedList would be good if you do not know the final size of the list, and you do more insert operations than read.

ArrayList is the oposite: more you read, and less add/remove. Because ArrayList under the hood holds an array, which must be rescaled when adding new elements, but never get's reduced, when you remove elements.

Answer 2

I'm on my phone at the moment so I can't promise that this will be syntactically perfect, but here's how you can do it with a Stream:

processeditemList.values().stream()
    .flatMap(e -> e.keySet().stream())
    .collect(Collectors.toCollection(LinkedList::new));

I'm unable to test it currently, but I'll look over the Javadocs and change anything if it's incorrect.

Edit: I think everything is good. If it doesn't matter which List implementation is used, you can change

Collectors.toCollection(LinkedList::new)

to

Collectors.toList()