I'm using ui-router for state handling. This works fine, but now I have to create page 404 and would like to display it on the whole page and not inside the page as other pages.
app.config(['$stateProvider', '$urlRouterProvider', '$locationProvider',
function ($stateProvider, $urlRouterProvider, $locationProvider) {
$locationProvider.hashPrefix('!').html5Mode({
enabled: true,
requireBase: false
});
$stateProvider
.state('stateIndex', {
url: '/',
templateUrl: '/templates/list.html',
controller: 'dashListController'
})
.state('stateList', {
url: '/list',
templateUrl: '/templates/list.html',
controller: 'dashListController'
}).state('stateDashboard', {
url: '/dashboard/:id',
templateUrl: '/templates/dashboard.html',
controller: 'dashboardController'
})
.state('stateWidgetsList', {
url: '/widgetsList',
templateUrl: '/templates/widgetsList.html',
controller: 'widgetsListController'
})
.state('404', {
url: '/404',
templateUrl: '/templates/404.html'
});
}]);
and on my index.html I have
<div ui-view></div>
where I display all the pages, outside of this I have logo, menu, etc.. which I would like to hide while displaying 404 page.
How can I do it?
Personally I would redesign the index.html, and bring the outer template (logo, menu, etc), into it's own template and state. Then you can sit child states below it in the ui-router hierarchy. For example:
$stateProvider
.state('app', {
abstract: true,
url: '',
templateUrl: '/templates/appcontainer.html'
})
.state('app.stateIndex', {
url: '/',
templateUrl: '/templates/list.html',
controller: 'dashListController'
})
.state('404', {
url: '/404',
templateUrl: '/templates/404.html'
});
Then you just need to put your logos/menus, etc inside appcontainer.html
, and then just have a single <div ui-view></div>
inside your index.html. Also if you do it this way, don't forget to add the child ui-view
inside appcontainer.html
.
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