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How to display a 3D plot of a 3D array isosurface in matplotlib mplot3D or similar?

I have a 3-dimensional numpy array. I'd like to display (in matplotlib) a nice 3D plot of an isosurface of this array (or more strictly, display an isosurface of the 3D scalar field defined by interpolating between the sample points).

matplotlib's mplot3D part provides nice 3D plot support, but (so far as I can see) its API doesn't have anything which will simply take a 3D array of scalar values and display an isosurface. However, it does support displaying a collection of polygons, so presumably I could implement the marching cubes algorithm to generate such polygons.

It does seem quite likely that a scipy-friendly marching cubes has already been implemented somewhere and that I haven't found it, or that I'm missing some easy way of doing this. Alternatively I'd welcome any pointers to other tools for visualising 3D array data easily usable from the Python/numpy/scipy world.

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timday Avatar asked May 17 '11 11:05

timday


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2 Answers

Just to elaborate on my comment above, matplotlib's 3D plotting really isn't intended for something as complex as isosurfaces. It's meant to produce nice, publication-quality vector output for really simple 3D plots. It can't handle complex 3D polygons, so even if implemented marching cubes yourself to create the isosurface, it wouldn't render it properly.

However, what you can do instead is use mayavi (it's mlab API is a bit more convenient than directly using mayavi), which uses VTK to process and visualize multi-dimensional data.

As a quick example (modified from one of the mayavi gallery examples):

import numpy as np from enthought.mayavi import mlab  x, y, z = np.ogrid[-10:10:20j, -10:10:20j, -10:10:20j] s = np.sin(x*y*z)/(x*y*z)  src = mlab.pipeline.scalar_field(s) mlab.pipeline.iso_surface(src, contours=[s.min()+0.1*s.ptp(), ], opacity=0.3) mlab.pipeline.iso_surface(src, contours=[s.max()-0.1*s.ptp(), ],)  mlab.show() 

enter image description here

like image 162
Joe Kington Avatar answered Sep 21 '22 10:09

Joe Kington


Complementing the answer of @DanHickstein, you can also use trisurf to visualize the polygons obtained in the marching cubes phase.

import numpy as np from numpy import sin, cos, pi from skimage import measure import matplotlib.pyplot as plt from mpl_toolkits.mplot3d import Axes3D         def fun(x, y, z):     return cos(x) + cos(y) + cos(z)      x, y, z = pi*np.mgrid[-1:1:31j, -1:1:31j, -1:1:31j] vol = fun(x, y, z) iso_val=0.0 verts, faces = measure.marching_cubes(vol, iso_val, spacing=(0.1, 0.1, 0.1))  fig = plt.figure() ax = fig.add_subplot(111, projection='3d') ax.plot_trisurf(verts[:, 0], verts[:,1], faces, verts[:, 2],                 cmap='Spectral', lw=1) plt.show() 

enter image description here

Update: May 11, 2018

As mentioned by @DrBwts, now marching_cubes return 4 values. The following code works.

import numpy as np from numpy import sin, cos, pi from skimage import measure import matplotlib.pyplot as plt from mpl_toolkits.mplot3d import Axes3D   def fun(x, y, z):     return cos(x) + cos(y) + cos(z)  x, y, z = pi*np.mgrid[-1:1:31j, -1:1:31j, -1:1:31j] vol = fun(x, y, z) iso_val=0.0 verts, faces, _, _ = measure.marching_cubes(vol, iso_val, spacing=(0.1, 0.1, 0.1))  fig = plt.figure() ax = fig.add_subplot(111, projection='3d') ax.plot_trisurf(verts[:, 0], verts[:,1], faces, verts[:, 2],                 cmap='Spectral', lw=1) plt.show() 

Update: February 2, 2020

Adding to my previous answer, I should mention that since then PyVista has been released, and it makes this kind of tasks somewhat effortless.

Following the same example as before.

from numpy import cos, pi, mgrid import pyvista as pv  #%% Data x, y, z = pi*mgrid[-1:1:31j, -1:1:31j, -1:1:31j] vol = cos(x) + cos(y) + cos(z) grid = pv.StructuredGrid(x, y, z) grid["vol"] = vol.flatten() contours = grid.contour([0])  #%% Visualization pv.set_plot_theme('document') p = pv.Plotter() p.add_mesh(contours, scalars=contours.points[:, 2], show_scalar_bar=False) p.show() 

With the following result

enter image description here

Update: February 24, 2020

As mentioned by @HenriMenke, marching_cubes has been renamed to marching_cubes_lewiner. The "new" snippet is the following.

import numpy as np from numpy import cos, pi from skimage.measure import marching_cubes_lewiner import matplotlib.pyplot as plt from mpl_toolkits.mplot3d import Axes3D  x, y, z = pi*np.mgrid[-1:1:31j, -1:1:31j, -1:1:31j] vol = cos(x) + cos(y) + cos(z) iso_val=0.0 verts, faces, _, _ = marching_cubes_lewiner(vol, iso_val, spacing=(0.1, 0.1, 0.1))  fig = plt.figure() ax = fig.add_subplot(111, projection='3d') ax.plot_trisurf(verts[:, 0], verts[:,1], faces, verts[:, 2], cmap='Spectral',                 lw=1) plt.show() 
like image 41
nicoguaro Avatar answered Sep 21 '22 10:09

nicoguaro