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How to determine if win32api.ShellExecute was successful using hinstance?

I've been looking around for an answer to my original issue.. how do i determine (programmatically) that my win32api.ShellExecute statement executed successfully, and if a successful execution occurs, execute an os.remove() statement.

Researching I found out that the ShellExecute() call returns the HINSTANCE. Further digging I found that ShellExecute() will return an HINSTANCE > 32 if it was successful. My problem/question now is, how do i use it to control the rest of my program's flow? I tried using an if HINSTANCE> 32: statement to control the next part, but I get a NameError: name 'hinstance' is not defined message. Normally this wouldn't confuse me because it means i need to define the variable 'hinstance' before referencing it; however, because i thought ShellExecute is supposed to return HINSTANCE, i thought that makes it available for use?

Here is my full code where i am trying to implement this. Note that in my print_file() def i am assigning hinstance to the full win32api.ShellExecute() command in attempt to capture the hinstance along with explicitly returning it at the end of the function.. this isn't working either.

import win32print
import win32api
from os.path import isfile, join
import glob
import os
import time

source_path = "c:\\temp\\source\\"

def main():
    printer_name = win32print.GetDefaultPrinter()
    while True:
        file_queue = [f for f in glob.glob("%s\\*.txt" % source_path) if isfile(f)]
        if len(file_queue) > 0:
            for i in file_queue:
                print_file(i, printer_name)
                if hinstance > 32:
                    time.sleep(.25)
                    delete_file(i)
                print "Filename: %r has printed" % i
                print
                time.sleep(.25)
                print                
        else:
            print "No files to print. Will retry in 15 seconds"
        time.sleep(15)


def print_file(pfile, printer):
    hinstance = win32api.ShellExecute(
        0,
        "print",
        '%s' % pfile,
        '/d:"%s"' % printer,
        ".",
        0
        )
    return hinstance


def delete_file(f):
    os.remove(f)
    print f, "was deleted!"

def alert(email):
    pass

main()
like image 498
CyberSamurai Avatar asked Aug 02 '13 20:08

CyberSamurai


1 Answers

With ShellExecute, you will never know when the printing is complete, it depends on the size of the file and whether the printer driver buffers the contents (the printer might be waiting for you to fill the paper tray, for example).

According to this SO answer, it looks like subprocess.call() is a better solution, since it waits for the command to complete, only in this case you would need to read the registry to obtain the exe associated with the file.

ShellExecuteEx is available from pywin32, you can do something like:

import win32com.shell.shell as shell
param = '/d:"%s"' % printer
shell.ShellExecuteEx(fmask = win32com.shell.shellcon.SEE_MASK_NOASYNC, lpVerb='print', lpFile=pfile, lpParameters=param)

EDIT: code for waiting on the handle from ShellExecuteEx()

import win32com.shell.shell as shell
import win32event
#fMask = SEE_MASK_NOASYNC(0x00000100) = 256 + SEE_MASK_NOCLOSEPROCESS(0x00000040) = 64
dict = shell.ShellExecuteEx(fMask = 256 + 64, lpFile='Notepad.exe', lpParameters='Notes.txt')
hh = dict['hProcess']
print hh
ret = win32event.WaitForSingleObject(hh, -1)
print ret
like image 138
Edward Clements Avatar answered Oct 20 '22 09:10

Edward Clements