Code first.
#include <iostream> using namespace std; struct A final {}; struct B {}; int main() { cout << is_final<A>::value << endl; // Output true cout << is_final<B>::value << endl; // Output false return 0; }
How to implement the class is_final?
Final keyword have the following purposes in C++ Note: the main difference with final keyword in Java is , a) final is not actually a keyword in C++. you can have a variable named as final in C++ b) In Java, final keyword is always added before the class keyword.
2nd use of final specifier: final specifier in C++ 11 can also be used to prevent inheritance of class / struct. If a class or struct is marked as final then it becomes non inheritable and it cannot be used as base class/struct. The following program shows use of final specifier to make class non inheritable: CPP.
C++ has no direct method to check one object is an instance of some class type or not. In Java, we can get this kind of facility. In C++11, we can find one item called is_base_of<Base, T>. This will check if the given class is a base of the given object or not.
Grammar. The try-finally statement is a Microsoft extension to the C and C++ languages that enable target applications to guarantee execution of cleanup code when execution of a block of code is interrupted. Cleanup consists of such tasks as deallocating memory, closing files, and releasing file handles.
As the implementer of GCC's __is_final
intrinisic (for PR 51365) I'm pretty sure it can't be done in a library, it needs compiler support.
You can do some very clever things with C++11's SFINAE for expressions feature but to detect whether a class is final you'd need to derive from it, and instantiate the derived type, in a template argument deduction context, but deriving from a class is done in a declaration not an expression.
Also, you should think about whether you only want to know if the final
pseudo-keyword was used, or if a class is un-derivable for other reasons, such as having only private constructors.
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