I am trying to determine whether the device being used is iPhone or iPad.
Please see this question: Detect current device with UI_USER_INTERFACE_IDIOM() in Swift
That solution works if you use UIKit. But
What is the equivalent method if you are using SwiftUI ?
To detect current device with iOS/Swift we can use UserInterfaceIdiom. It is an enum in swift, which tells which device is being used. The interface idiom provides multiple values in it's enum which are.
Getting The Model CodeThe model code is close to the device name, but not exactly. For example an iPhone 11 Pro Max has the model code iPhone12,5 . This will print for example x86_64 if you are using a simulator or iPhone12,5 if you are using a real iPhone 11 Pro Max it will say iPhone12,5 .
The Swift Playgrounds iPad app has recently added support for SwiftUI, as well as the Combine framework which provides new ways to handle asynchronous events.
You can find the device type, like this:
if UIDevice.current.userInterfaceIdiom == .pad {
...
}
You can use this:
UIDevice.current.localizedModel
In your case, an implementation method could be:
if UIDevice.current.localizedModel == "iPhone" {
print("This is an iPhone")
} else if UIDevice.current.localizedModel == "iPad" {
print("This is an iPad")
}
Obviously, you can use this for string interpolation such as this (assuming the current device type is an iPhone):
HStack {
Text("Device Type: ")
Text(UIDevice.current.localizedModel)
}
//Output:
//"Device Type: iPhone"
It will return the device type. (iPhone, iPad, AppleWatch) No further imports are necessary aside from SwiftUI which should have already been imported upon creation of your project if you selected SwiftUI as the interface.
NOTE: It does not return the device model (despite the ".localizedModel")
Hope this helps!
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