There are two arrays in JavaScript, they are both in the following format:
[{'drink':['alcohol', 'soft', 'hot']}, {'fruit':['apple', 'pear']}];
I need to detect if the two arrays are equal or not. they are considered equal if they contain the same elements in a different order. How can I make that?
If 1
and 2
are both the same, your array is equal.
Looping through true arrays can be achieved through for(var i=0; i<array.length; i++)
.
Walking through the properties of such an object can be done by for(var i in object)
.
function recursiveCompare(obj, reference){
if(obj === reference) return true;
if(obj.constructor !== reference.constructor) return false;
if(obj instanceof Array){
if(obj.length !== reference.length) return false;
for(var i=0, len=obj.length; i<len; i++){
if(typeof obj[i] == "object" && typeof reference[j] == "object"){
if(!recursiveCompare(obj[i], reference[i])) return false;
}
else if(obj[i] !== reference[i]) return false;
}
}
else {
var objListCounter = 0;
var refListCounter = 0;
for(var i in obj){
objListCounter++;
if(typeof obj[i] == "object" && typeof reference[i] == "object"){
if(!recursiveCompare(obj[i], reference[i])) return false;
}
else if(obj[i] !== reference[i]) return false;
}
for(var i in reference) refListCounter++;
if(objListCounter !== refListCounter) return false;
}
return true; //Every object and array is equal
}
If you don't understand the function, feel free to request an explanation at the comments.
With Javascript, you can't check if arrays are equals, but you can compare them like this:
var arr1 = ['alcohol', 'soft', 'hot'],
arr2 = ['apple', 'pear'],
arr3 = ['soft', 'hot', 'alcohol'];
function isSame(a1, a2){
return !(a1.sort() > a2.sort() || a1.sort() < a2.sort());
}
console.log( isSame(arr1, arr2) ); //false
console.log( isSame(arr1, arr3) ); //true
The sort
put all elements in the same order, and if both <
and >
comparisons are false it means both are the same.
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