How to detect 404 response code from IO exception?

Question

How are you suppose to detect a 404 from an IO exception. I could just search the error message for "404", but is that the correct way? Anything more direct?

  import com.google.api.services.drive.model.File;
  import com.google.api.services.drive.Drive.Files.Update;
  import com.google.api.services.drive.Drive;


    File result = null;

    try {

        update = drive.files().update(driveId, file , mediaContent);
        update.setNewRevision(true);

        result = update.execute();

    } catch (IOException e) {

        Log.e(TAG, "file update exception, statusCode: " + update.getLastStatusCode());
        Log.e(TAG, "file update exception, e: " + e.getMessage());

    }   

Log.e(TAG, "file update exception, statuscode " + update.getLastStatusCode());

03-03 05:04:31.738: E/System.out(31733): file update exception, statusCode: -1
03-03 05:04:31.738: E/System.out(31733): file update exception, e: 404 Not Found
03-03 05:04:31.738: E/System.out(31733): "message": "File not found: FileIdRemoved",

Answer: Aegan's comment below was correct, turns out you can subclass the the exception to a GoogleJsonResponseException and from there get the status code. The answer in this case ultimately depended on the fact I am using a GoogleClient, which generates a subclass of IO Exception that contains the status code.

Example:

Try{
    ...
    }catch (IOException e) {

      if(e instanceof GoogleJsonResponseException){
          int statusCode = ((GoogleJsonResponseException) e).getStatusCode();
          //do something
   }
 }

Answer 1

Handle HttpResponseException:

catch (HttpResponseException hre) {
   if (hre.getStatusCode() == 404) {
      // TODO: Handle Http 404 
   }
}

Detail: AbstractGoogleClientRequest creates exceptions.See source code

execute method calls executeUnparsed. executeUnparsed creates exception with newExceptionOnError. There you will see, it throws a HttpResponseException(which is a subclass of IOException)