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For example I have this document:
db.test.save({
_id: 1,
list: [
{ key: "a" },
{ key: "b" },
{ key: "c" },
{ key: "d" },
{ key: "e" }
]
})
and I need remove to the second element from the list.
For now I do that in two steps. I first unset the second list element but the $unset operator doesn't remove the element, it modifies it to null, and after that I pull any nullable value from the list field:
db.test.update({_id: 1}, {$unset: {"list.2": 1}})
db.test.update({_id: 1}, {$pull: {list: null}})
Is there a solution to do that in one operation?
401
To remove an element, update, and use $pull in MongoDB. The $pull operator removes from an existing array all instances of a value or values that match a specified condition.
Use Array#splice method to remove an element from the array. Where the first argument is defined as the index and second as the number elements to be deleted. To remove elements at 3rd position use a while loop which iterates in backward and then delete the element based on the position.
No, unfortunately what you are doing is currently the best option. Have a look at this question: In mongoDb, how do you remove an array element by its index which links to a Jira for this very issue.
161
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