How to delete N numbers of documents in mongodb

Question

In my collections, documents contains key like status and timestamp. When I want to find latest ten documents then I write following query

db.collectionsname.find().sort({"timestamp"-1}).limit(10) 

This query gives me results which I want but when I want to delete latest ten documents then I was writing the following query

db.collectionsname.remove({"status":0},10).sort({"timestamp":-1}) 

but it shows following error TypeError: Cannot call method 'sort' of undefined and again I wrote the same query as below db.collectionsname.remove({"status":0},10) It deletes only one document. So how can I write a query which deletes ten latest documents and sorts on timestamp?

Answer 1

You can't set a limit when using remove or findAndModify. So, if you want to precisely limit the number of documents removed, you'll need to do it in two steps.

db.collectionName.find({}, {_id : 1})     .limit(100)     .sort({timestamp:-1})     .toArray()     .map(function(doc) { return doc._id; });  // Pull out just the _ids 

Then pass the returned _ids to the remove method:

db.collectionName.remove({_id: {$in: removeIdsArray}}) 

FYI: you cannot remove documents from a capped collection.

Answer 2

Let N be number of records to delete.

    db.collectionName.find().limit(N).forEach(doc =>       {         db.collectionName.remove({_id:doc._id})      }     )