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How to define a cost function in nolearn, lasagne?

I'm doing a neural network in nolearn, a Theano based library that uses lasagne.

I'm not understanding how do I define my own cost function.

The output layer is only 3 neurons [0, 1, 2] and I want it to be mostly sure when it gives 1 or 2, but otherwise - if it isn't really sure of 1, 2 - to give back simply 0.

So, I came up with a cost function (will need tuning) where the cost is double for 1 and 2 than for 0, but I can't understand how to tell this to the network.

# optimization method:
from lasagne.updates import sgd
update=sgd,
update_learning_rate=0.0001

This is the code for the update, but how to I tell SGD to use my cost function instead of it's own?

EDIT: The full net code is:

def nn_loss(data, x_period, columns, num_epochs, batchsize, l_rate=0.02):
    net1 = NeuralNet(
        layers=[('input', layers.InputLayer),
                ('hidden1', layers.DenseLayer),
                ('output', layers.DenseLayer),
                ],
        # layer parameters:
        batch_iterator_train=BatchIterator(batchsize),
        batch_iterator_test=BatchIterator(batchsize),

        input_shape=(None, int(x_period*columns)),
        hidden1_nonlinearity=lasagne.nonlinearities.rectify,
        hidden1_num_units=100,  # number of units in 'hidden' layer
        output_nonlinearity=lasagne.nonlinearities.sigmoid,
        output_num_units=3,

        # optimization method:
        update=nesterov_momentum,
        update_learning_rate=5*10**(-3),
        update_momentum=0.9,
        on_epoch_finished=[
            EarlyStopping(patience=20),
        ],
        max_epochs=num_epochs,
        verbose=1,

        # Here are the important parameters for multi labels
        regression=True,
        # objective_loss_function=multilabel_objective,
        # custom_score=("validation score", lambda x, y: np.mean(np.abs(x - y)))
        )

    # Train the network
    start_time = time.time()
    net1.fit(data['X_train'], data['y_train'])
}

EDIT Error when using regression=True

Got 99960 testing datasets.
# Neural Network with 18403 learnable parameters

## Layer information

  #  name       size
---  -------  ------
  0  input       180
  1  hidden1     100
  2  output        3

Traceback (most recent call last):
  File "/Users/morgado/anaconda/lib/python3.4/site-packages/theano/compile/function_module.py", line 607, in __call__
    outputs = self.fn()
ValueError: GpuElemwise. Input dimension mis-match. Input 1 (indices start at 0) has shape[1] == 1, but the output's size on that axis is 3.

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "train_nolearn_simple.py", line 272, in <module>
    main(**kwargs)
  File "train_nolearn_simple.py", line 239, in main
    nn_loss_fit = nn_loss(data, x_period, columns, num_epochs, batchsize)
  File "train_nolearn_simple.py", line 217, in nn_loss
    net1.fit(data['X_train'], data['y_train'])
  File "/Users/morgado/anaconda/lib/python3.4/site-packages/nolearn/lasagne/base.py", line 416, in fit
    self.train_loop(X, y)
  File "/Users/morgado/anaconda/lib/python3.4/site-packages/nolearn/lasagne/base.py", line 462, in train_loop
    self.train_iter_, Xb, yb)
  File "/Users/morgado/anaconda/lib/python3.4/site-packages/nolearn/lasagne/base.py", line 516, in apply_batch_func
    return func(Xb) if yb is None else func(Xb, yb)
  File "/Users/morgado/anaconda/lib/python3.4/site-packages/theano/compile/function_module.py", line 618, in __call__
    storage_map=self.fn.storage_map)
  File "/Users/morgado/anaconda/lib/python3.4/site-packages/theano/gof/link.py", line 297, in raise_with_op
    reraise(exc_type, exc_value, exc_trace)
  File "/Users/morgado/anaconda/lib/python3.4/site-packages/six.py", line 658, in reraise
    raise value.with_traceback(tb)
  File "/Users/morgado/anaconda/lib/python3.4/site-packages/theano/compile/function_module.py", line 607, in __call__
    outputs = self.fn()
ValueError: GpuElemwise. Input dimension mis-match. Input 1 (indices start at 0) has shape[1] == 1, but the output's size on that axis is 3.
Apply node that caused the error: GpuElemwise{Sub}[(0, 1)](GpuElemwise{Composite{scalar_sigmoid((i0 + i1))}}[(0, 0)].0, GpuFromHost.0)
Toposort index: 22
Inputs types: [CudaNdarrayType(float32, matrix), CudaNdarrayType(float32, matrix)]
Inputs shapes: [(200, 3), (200, 1)]
Inputs strides: [(3, 1), (1, 0)]
Inputs values: ['not shown', 'not shown']
Outputs clients: [[GpuCAReduce{pre=sqr,red=add}{1,1}(GpuElemwise{Sub}[(0, 1)].0), GpuElemwise{Mul}[(0, 0)](GpuElemwise{Sub}[(0, 1)].0, GpuElemwise{Composite{scalar_sigmoid((i0 + i1))}}[(0, 0)].0, GpuElemwise{sub,no_inplace}.0), GpuElemwise{mul,no_inplace}(CudaNdarrayConstant{[[ 2.]]}, GpuElemwise{Composite{(inv(i0) / i1)},no_inplace}.0, GpuElemwise{Sub}[(0, 1)].0, GpuElemwise{Composite{scalar_sigmoid((i0 + i1))}}[(0, 0)].0, GpuElemwise{sub,no_inplace}.0)]]

HINT: Re-running with most Theano optimization disabled could give you a back-trace of when this node was created. This can be done with by setting the Theano flag 'optimizer=fast_compile'. If that does not work, Theano optimizations can be disabled with 'optimizer=None'.
HINT: Use the Theano flag 'exception_verbosity=high' for a debugprint and storage map footprint of this apply node.
like image 719
jbssm Avatar asked Aug 22 '15 01:08

jbssm


1 Answers

When you instantiate your neural network, you can pass a custom loss function that you've defined previously:

import theano.tensor as T
import numpy as np
from nolearn.lasagne import NeuralNet
# I'm skipping other inputs for the sake of concision

def multilabel_objective(predictions, targets):
    epsilon = np.float32(1.0e-6)
    one = np.float32(1.0)
    pred = T.clip(predictions, epsilon, one - epsilon)
    return -T.sum(targets * T.log(pred) + (one - targets) * T.log(one - pred), axis=1)

net = NeuralNet(
    # your other parameters here (layers, update, max_epochs...)
    # here are the one you're interested in:
    objective_loss_function=multilabel_objective,
    custom_score=("validation score", lambda x, y: np.mean(np.abs(x - y)))
    )

As you can see, it's also possible to define a custom score (using the keyword custom_score)

like image 196
P. Camilleri Avatar answered Sep 21 '22 23:09

P. Camilleri