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How to decrypt password from JavaScript CryptoJS.AES.encrypt(password, passphrase) in Python

I have a password which is encrypt from JavaScript via

  var password = 'sample'
  var passphrase ='sample_passphrase'
  CryptoJS.AES.encrypt(password, passphrase)

Then I tried to decrypt the password comes from JavaScript in Python:

  from Crypto.Cipher import AES
  import base64

  PADDING = '\0'

  pad_it = lambda s: s+(16 - len(s)%16)*PADDING
  key = 'sample_passphrase'
  iv='11.0.0.101'        #------> here is my question, how can I get this iv to restore password, what should I put here?
  key=pad_it(key)        #------> should I add padding to keys and iv?
  iv=pad_it(iv)          ##
  source = 'sample'
  generator = AES.new(key, AES.MODE_CFB,iv)
  crypt = generator.encrypt(pad_it(source))
  cryptedStr = base64.b64encode(crypt)
  print cryptedStr
  generator = AES.new(key, AES.MODE_CBC,iv)
  recovery = generator.decrypt(crypt)
  print recovery.rstrip(PADDING)

I checked JS from browser console, it shows IV in CryptoJS.AES.encrypt(password, passphrase) is a object with some attributes( like sigBytes:16, words: [-44073646, -1300128421, 1939444916, 881316061]). It seems generated randomly.

From one web page, it tells me that JS has two way to encrypt password (reference link ):

  • a. crypto.createCipher(algorithm, password)
  • b. crypto.createCipheriv(algorithm, key, iv)

What I saw in JavaScript should be option a. However, only option b is equivalent to AES.new() in python.

The questions are:

  1. How can I restore this password in Python without changing JavaScript code?

  2. If I need IV in Python, how can I get it from the password that is used in JavaScript?

like image 554
Bing Avatar asked Apr 21 '16 07:04

Bing


People also ask

What is secret passphrase in CryptoJS?

It means that the key (secret passphrase) used to encrypt and decrypt is the same. So, it's security relies mostly in keeping the key secure. If someone obtains the key, they will be able to decrypt anything encrypted with that passphrase.


1 Answers

You will have to implement OpenSSL's EVP_BytesToKey, because that is what CryptoJS uses to derive the key and IV from the provided password, but pyCrypto only supports the key+IV type encryption. CryptoJS also generates a random salt which also must be send to the server. If the ciphertext object is converted to a string, then it uses automatically an OpenSSL-compatible format which includes the random salt.

var data = "Some semi-long text for testing";
var password = "some password";
var ctObj = CryptoJS.AES.encrypt(data, password);
var ctStr = ctObj.toString();

out.innerHTML = ctStr;
<script src="https://cdn.rawgit.com/CryptoStore/crypto-js/3.1.2/build/rollups/aes.js"></script>
<div id="out"></div>

Possible output:

U2FsdGVkX1+ATH716DgsfPGjzmvhr+7+pzYfUzR+25u0D7Z5Lw04IJ+LmvPXJMpz

CryptoJS defaults to 256 bit key size for AES, PKCS#7 padding and CBC mode. AES has a 128 bit block size which is also the IV size. This means that we have to request 32+16 = 48 byte from EVP_BytesToKey. I've found a semi-functional implementation here and extended it further.

Here is the full Python (tested with 2.7 and 3.4) code, which is compatible with CryptoJS:

from Cryptodome import Random
from Cryptodome.Cipher import AES
import base64
from hashlib import md5

BLOCK_SIZE = 16

def pad(data):
    length = BLOCK_SIZE - (len(data) % BLOCK_SIZE)
    return data + (chr(length)*length).encode()

def unpad(data):
    return data[:-(data[-1] if type(data[-1]) == int else ord(data[-1]))]

def bytes_to_key(data, salt, output=48):
    # extended from https://gist.github.com/gsakkis/4546068
    assert len(salt) == 8, len(salt)
    data += salt
    key = md5(data).digest()
    final_key = key
    while len(final_key) < output:
        key = md5(key + data).digest()
        final_key += key
    return final_key[:output]

def encrypt(message, passphrase):
    salt = Random.new().read(8)
    key_iv = bytes_to_key(passphrase, salt, 32+16)
    key = key_iv[:32]
    iv = key_iv[32:]
    aes = AES.new(key, AES.MODE_CBC, iv)
    return base64.b64encode(b"Salted__" + salt + aes.encrypt(pad(message)))

def decrypt(encrypted, passphrase):
    encrypted = base64.b64decode(encrypted)
    assert encrypted[0:8] == b"Salted__"
    salt = encrypted[8:16]
    key_iv = bytes_to_key(passphrase, salt, 32+16)
    key = key_iv[:32]
    iv = key_iv[32:]
    aes = AES.new(key, AES.MODE_CBC, iv)
    return unpad(aes.decrypt(encrypted[16:]))


password = "some password".encode()
ct_b64 = "U2FsdGVkX1+ATH716DgsfPGjzmvhr+7+pzYfUzR+25u0D7Z5Lw04IJ+LmvPXJMpz"

pt = decrypt(ct_b64, password)
print("pt", pt)

print("pt", decrypt(encrypt(pt, password), password))

Similar code can be found in my answers for Java and PHP.

JavaScript AES encryption in the browser without HTTPS is simple obfuscation and does not provide any real security, because the key must be transmitted alongside the ciphertext.

[UPDATE]:

You should use pycryptodome instead of pycrypto because pycrypto(latest pypi version is 2.6.1) no longer maintained and it has vulnerabilities CVE-2013-7459 and CVE-2018-6594 (CVE warning reported by github). I choose pycryptodomex package here(Cryptodome replace Crypto in code) instead of pycryptodome package to avoid conflict name with Crypto from pycrypto package.

like image 194
Artjom B. Avatar answered Oct 01 '22 22:10

Artjom B.