How to declare a typescript property that implements multiple interfaces

Question

Say I have 2 interfaces:

interface Interface1{}
interface Interface2{}

is there a way to declare a property as implementing both interfaces? Something like:

class MyClass{
  public p: Interface1, Interface2
}

Answer 1

is there a way to declare a property as implementing both interfaces? Something like:

Yup. An intersection type:

interface Interface1{}
interface Interface2{}
class MyClass{
  public p: Interface1 & Interface2
}

More

• TypeScript Intersection Types: https://basarat.gitbook.io/typescript/type-system#intersection-type