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In the following code, I would like to have a counter to keep track of the number of Person objects created. This code is not doing so, how would I accomplish that?
function Person(){ this.name = "Peter"; this.counter = this.counter + 1; alert(this.counter); } Person.prototype.counter = 0; var p1 = new Person; var p2 = new Person; 
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Yes it is. Each of your b variables is private to the function in which they are declared. Show activity on this post. b in func and b in main are two different variables, they are not related, and their scope is inside each function that they are in.
Static variable in JavaScript: We used the static keyword to make a variable static just like the constant variable is defined using the const keyword. It is set at the run time and such type of variable works as a global variable. We can use the static variable anywhere.
JavaScript const can be used with objects and arrays also. The value for a static variable can be reassigned. The value for a const variable cannot be reassigned. However, we can re-declare the const variable in different block scope as it is allowed.
Can we override a static method? No, we cannot override static methods because method overriding is based on dynamic binding at runtime and the static methods are bonded using static binding at compile time.
function Person(){ this.name = "Peter"; Person.counter++; alert(Person.counter); } Person.counter = 0; var p1 = new Person(); var p2 = new Person(); Make the "static" variable a property of the Person function, rather than the prototype, and use Person instead of this inside the constructor.
This is possible because JavaScript functions are first-class (i.e. they are objects), so can have properties of their own.
Here's a working example of the above code.
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