how to curry a method?

Question

consider this code

def f x, y
  x + y
end

g = lambda(&method(:f)).curry.(1)

g.(2) # => 3

the expression for g is too hard to read. Can it be simplified?

Answer 1

If you are using Ruby 2.2.0 or later, you can use Method#curry:

def f(x, y)
  x + y
end
g = method(:f).curry[1]
p g[2] # => 3