How to create multiple (but individual) empty lists in Python?

Question

I wrote a script that at one point generates a bunch of empty lists applying a code with the structure:

A,B,C,D=[],[],[],[]

which produces the output:

A=[]
B=[]
C=[]
D=[]

The way it is right now, I have to manually modify the letters each time I use a different dataset as an input. I want to be able to automatize that. I thought about doing this:

FieldList=[A,B,C,D]
bracket=[]
[[0]for field in FieldList]
for field in FieldList:
    bracket=bracket+["[]"]
FieldList=bracket                  

Here I was trying to replicate " A,B,C,D=[],[],[],[]", but evidently that's not how it works.

I also tried:

FieldList=[A,B,C,D]
bracket=[]
[[0]for field in FieldList]
for field in FieldList:
    field=[]

But at the end it just produces a single list call "field".

#

So, this is what I need the lists for. I will be reading information from a csv and adding the data I'm extracting from each row to the lists. If generate a "list of lists", can I still call each of them individually to append stuff to them?

A,B,C,D=[],[],[],[]
with open(csvPath+TheFile, 'rb') as csvfile:    #Open the csv table
    r = csv.reader(csvfile, delimiter=';')      #Create an iterator with all the rows of the csv file, indicating the delimiter between columns
    for i,row in enumerate(r):                  #For each row in the csv
        if i > 0:                               #Skip header 
            A.append(float(row[0]))             #Extract the information and append it to each corresponding list
            B.append(float(row[1]))
            C.append(format(row[2]))
            D.append(format(row[3]))

Answer 1

You are overcomplicating things. Just use a list or dictionary:

fields = {key: [] for key in 'ABCD'}

then refer to fields['A'], etc. as needed, or loop over the structure to process each in turn.