How do I create an identity matrix with numpy? Is there a simpler syntax than
numpy.matrix(numpy.identity(n))
                Here's a simpler syntax:
np.matlib.identity(n)
And here's an even simpler syntax that runs much faster:
In [1]: n = 1000
In [2]: timeit np.matlib.identity(n)
100 loops, best of 3: 8.78 ms per loop
In [3]: timeit np.matlib.eye(n)
1000 loops, best of 3: 695 us per loop
                        Also np.eye can be used to create an identity array (In).
For example,
>>> np.eye(2, dtype=int)
array([[1, 0],
       [0, 1]])
>>> np.eye(3, k=1)
array([[ 0.,  1.,  0.],
       [ 0.,  0.,  1.],
       [ 0.,  0.,  0.]])
                        If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With