How do I create an identity matrix with numpy? Is there a simpler syntax than
numpy.matrix(numpy.identity(n))
Here's a simpler syntax:
np.matlib.identity(n)
And here's an even simpler syntax that runs much faster:
In [1]: n = 1000
In [2]: timeit np.matlib.identity(n)
100 loops, best of 3: 8.78 ms per loop
In [3]: timeit np.matlib.eye(n)
1000 loops, best of 3: 695 us per loop
Also np.eye can be used to create an identity array (In).
For example,
>>> np.eye(2, dtype=int)
array([[1, 0],
[0, 1]])
>>> np.eye(3, k=1)
array([[ 0., 1., 0.],
[ 0., 0., 1.],
[ 0., 0., 0.]])
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