I have a set of cpp files that I want to compile directly into a binary and also to compile into a shared library.
I have
bin_PROGRAMS=mybin
lib_LTLIBRARIES=libmylib.la
COMMON_SOURCES=f1.cpp f2.cpp f3.cpp
mybin_SOURCES=main.cpp $(COMMON_SOURCES)
libmylib_la_SOURCES=$(COMMON_SOURCES)
When I run this the cpp files are compiled twice, once with libtool and once without and sometimes libtool/automake complains
Makefile.am: object `f1.$(OBJEXT)' created both with libtool and without`
I tried putting COMMON_SOURCES into a .a file but then libtool complains when I link a .a with a .la (saying its not portable).
What I need is something like
bin_LTPROGRAMS=mybin
but that doesnt exist
edit: clarification - I am using automake/autoconf. What I have shown above is the meat of my automake Makefile.am
Link against the library of common sources specifically:
bin_PROGRAMS = mybin
lib_LTLIBRARIES = libmylib.la
mybin_SOURCES = main.cpp
mybin_LDADD = libmylib.la
libmylib_la_SOURCES = f1.cpp f2.cpp f3.cpp
If libmylib.la
ends up using files that shouldn't be linked into mybin
, create a libtool convenience library, using a Makefile.am
something like this:
bin_PROGRAMS = mybin
noinst_LTLIBRARIES = libcommon.la
lib_LTLIBRARIES = libmylib.la
mybin_SOURCES = main.cpp
mybin_LDADD = libcommon.la
libmylib_la_SOURCES = f4.cpp f5.cpp f6.cpp
libmylib_la_LIBADD = libcommon.la
libcommon_la_SOURCES = f1.cpp f2.cpp f3.cpp
This will link f1.cpp
, f2.cpp
, f3.cpp
, f4.cpp
, f5.cpp
and f6.cpp
into libmylib.la
and main.cpp
, f1.cpp
, f2.cpp
and f3.cpp
into mybin
.
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