How to create an MKMapRect given two points, each specified with a latitude and longitude value?

Question

I have a custom class that extends NSObject and implements the MKOverlay protocol. As a result, I need to implement the protocol's boundingMapRect property which is an MKMapRect. To create an MKMapRect I can of course use MKMapRectMake to make one. However, I don't know how to create an MKMapRect using that data I have which is two points, each specified by a latitude and longitude. MKMapRectMake's docs state:

MKMapRect MKMapRectMake(     double x,     double y,     double width,     double height );  Parameters x     The point along the east-west axis of the map projection to use for the origin. y     The point along the north-south axis of the map projection to use for the origin. width     The width of the rectangle (measured using map points). height     The height of the rectangle (measured using map points). Return Value     A map rectangle with the specified values. 

The latitude and longitude values I have to spec out the MKMapRect are:

24.7433195, -124.7844079 49.3457868, -66.9513812 

The target MKMapRect would therefore need to spec out an area that looks about like this:

So, to reiterate, how do I use my lat/lon values to create an MKMapRect that I can set as MKOverlay protocol's @property (nonatomic, readonly) MKMapRect boundingMapRect property?

Answer 1

This should do it:

// these are your two lat/long coordinates CLLocationCoordinate2D coordinate1 = CLLocationCoordinate2DMake(lat1,long1); CLLocationCoordinate2D coordinate2 = CLLocationCoordinate2DMake(lat2,long2);  // convert them to MKMapPoint MKMapPoint p1 = MKMapPointForCoordinate (coordinate1); MKMapPoint p2 = MKMapPointForCoordinate (coordinate2);  // and make a MKMapRect using mins and spans MKMapRect mapRect = MKMapRectMake(fmin(p1.x,p2.x), fmin(p1.y,p2.y), fabs(p1.x-p2.x), fabs(p1.y-p2.y)); 

this uses the lesser of the two x and y coordinates for your start point, and calculates the x/y spans between the two points for the width and height.