How to create a XML object from String in Java?

Question

I am trying to write a code that helps me to create a XML object. For example, I will give a string as input to a function and it will return me a XMLObject.

XMLObject convertToXML(String s) {} 

When I was searching on the net, generally I saw examples about creating XML documents. So all the things I saw about creating an XML and write on to a file and create the file. But I have done something like that:

Document document = new Document(); Element child = new Element("snmp"); child.addContent(new Element("snmpType").setText("snmpget")); child.addContent(new Element("IpAdress").setText("127.0.0.1")); child.addContent(new Element("OID").setText("1.3.6.1.2.1.1.3.0")); document.setContent(child); 

Do you think it is enough to create an XML object? and also can you please help me how to get data from XML? For example, how can I get the IpAdressfrom that XML?

Thank you all a lot

EDIT 1: Actually now I thought that maybe it would be much easier for me to have a file like base.xml, I will write all basic things into that for example:

<snmp> <snmpType><snmpType> <OID></OID> </snmp> 

and then use this file to create a XML object. What do you think about that?

Answer 1

If you can create a string xml you can easily transform it to the xml document object e.g. -

String xmlString = "<?xml version=\"1.0\" encoding=\"utf-8\"?><a><b></b><c></c></a>";    DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();   DocumentBuilder builder;   try {       builder = factory.newDocumentBuilder();       Document document = builder.parse(new InputSource(new StringReader(xmlString)));   } catch (Exception e) {       e.printStackTrace();   }  

You can use the document object and xml parsing libraries or xpath to get back the ip address.

Answer 2

try something like

public static Document loadXML(String xml) throws Exception {    DocumentBuilderFactory fctr = DocumentBuilderFactory.newInstance();    DocumentBuilder bldr = fctr.newDocumentBuilder();    InputSource insrc = new InputSource(new StringReader(xml));    return bldr.parse(insrc); }