I'm making some tedious calls to a bunch of functions, but the parameters will be determined at runtime. I wrote a simple function to keep my code DRY but giving it a name is unnecessary. I don't use this function anywhere else.
I'm trying to do it the way I would in Scheme, but I get a void-function
error:
(let ((do-work (lambda (x y z) (do-x x) (do-y y) ;; etc ))) (cond (test-1 (do-work 'a 'b 'c)) (test-2 (do-work 'i 'j 'k))))
I could stick it all into an apply
(e.g., (apply (lambda ...) (cond ...))
) but that isn't very readable. Is there a better way?
To define a function, we use the special form defun. It's followed by the function name and its arguments. The arguments are private, so it does not change anything outside the function. Any other symbol called inside a function will bring its value from outside since Elisp has global scope.
Emacs Lisp supports multiple programming styles or paradigms, including functional and object-oriented. Emacs Lisp is not a purely functional programming language since side effects are common. Instead, Emacs Lisp is considered an early functional flavored language.
By default, Common Lisp is lexically scoped, that is, every variable is lexically scoped except for special variables. By default, Emacs Lisp files are dynamically scoped, that is, every variable is dynamically scoped.
Emacs Lisp is a dialect of the Lisp programming language used as a scripting language by Emacs (a text editor family most commonly associated with GNU Emacs and XEmacs). It is used for implementing most of the editing functionality built into Emacs, the remainder being written in C, as is the Lisp interpreter.
Like other lisps (but not Scheme), Emacs Lisp has separate namespaces for variables and functions (i.e. it is a ‘Lisp2’, not a ‘Lisp1’; see Technical Issues of Separation in Function Cells and Value Cells for the origin and meaning of these terms).
You will need to use funcall
or apply
to call a lambda (or other function) that is stored in a variable.
(cond (test-1 (funcall do-work 'a 'b 'c)) (test-2 (funcall do-work 'i 'j 'k))
Use funcall
if you will always send the same number of arguments. Use apply
if you need to be able to send a variable number of arguments.
The internal mechanism is that each symbol has multiple “cells”. Which cell is used depends on where the symbol is in an evaluated form. When a symbol is the first element of an evaluated form, its “function” cell is used. In any other position, its “value” cell is used. In your code, do-work
has the function in its value cell. To access it as a function you use funcall
or apply
. If it were in the function cell, you could call it directly by using its name as the car of an evaluated form. You can accomplish this with flet
or labels
from the cl package.
Do (require 'cl)
to pull in the Common Lisp package, then use flet
instead of let
:
(flet ((do-work (x y z) (do-x x) (do-y y) ;; etc )) (cond (test-1 (do-work 'a 'b 'c)) (test-2 (do-work 'i 'j 'k))))
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