From two integers (1, 5)
one can create a range in the following way
1:5
[1] 1 2 3 4 5
How can you make a range of dates if you are give two dates ("2014-09-04 JST", "2014-09-11 JST")
The output must be
[1] ("2014-09-04 JST", "2014-09-05 JST", "2014-09-06 JST", "2014-09-07 JST", "2014-09-08 JST")
To create a sequence of dates we can leverage the seq() function. As with numeric vectors, you have to specify at least three of the four arguments ( from , to , by , and length. out ).
In R programming language range is an efficient way of finding the difference between maximum and minimum values within a vector or a data frame. A range () function is defined as the interval between the largest (maximum) and smallest (minimum) data value within a vector or column in a data frame in R.
Does this help?
seq(as.Date("2014/09/04"), by = "day", length.out = 5) # [1] "2014-09-04" "2014-09-05" "2014-09-06" "2014-09-07" "2014-09-08"
edit: adding in something about timezones
this works for my current timezone
seq(c(ISOdate(2014,4,9)), by = "DSTday", length.out = 5) #[1] "2014-04-09 08:00:00 EDT" "2014-04-10 08:00:00 EDT" "2014-04-11 08:00:00 EDT" "2014-04-12 08:00:00 EDT" #[5] "2014-04-13 08:00:00 EDT"
edit2:
OlsonNames() # I used this to find out what to write for the JST tz - it's "Japan" x <- as.POSIXct("2014-09-04 23:59:59", tz="Japan") format(seq(x, by="day", length.out=5), "%Y-%m-%d %Z") # [1] "2014-09-04 JST" "2014-09-05 JST" "2014-09-06 JST" "2014-09-07 JST" "2014-09-08 JST"
To get a sequence of dates ( days, weeks,.. ) using only start and end dates you can use:
seq(as.Date("2014/1/1"), as.Date("2014/1/10"), "days”) [1] "2014-01-01" "2014-01-02" "2014-01-03" "2014-01-04" "2014-01-05" "2014-01-06" "2014-01-07" [8] "2014-01-08" "2014-01-09" "2014-01-10”
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