Use the timedelta() class from the datetime module to add minutes to datetime, e.g. result = dt + timedelta(minutes=10) . The timedelta class can be passed a minutes argument and adds the specified number of minutes to the datetime.
To subtract hours from a given timestamp, we are going to use the datetime and timedelta classes of the datetime module. Step 1: If the given timestamp is in a string format, then we need to convert it to the datetime object. For that we can use the datetime. strptime() function.
import datetime and then the magic timedelta stuff:
In [63]: datetime.datetime.now()
Out[63]: datetime.datetime(2010, 12, 27, 14, 39, 19, 700401)
In [64]: datetime.datetime.now() - datetime.timedelta(minutes=15)
Out[64]: datetime.datetime(2010, 12, 27, 14, 24, 21, 684435)
datetime.datetime.now() - datetime.timedelta(minutes=15)
This is simply what to do:
datetime.datetime.now() - datetime.timedelta(minutes = 15)
timedelta
s are specifically designed to allow you to subtract or add deltas (differences) to datetime
s.
I have provide two methods for doing so for minutes as well as for years and hours if you want to see more examples:
import datetime
print(datetime.datetime.now())
print(datetime.datetime.now() - datetime.timedelta(minutes = 15))
print(datetime.datetime.now() + datetime.timedelta(minutes = -15))
print(datetime.timedelta(hours = 5))
print(datetime.datetime.now() + datetime.timedelta(days = 3))
print(datetime.datetime.now() + datetime.timedelta(days = -9))
print(datetime.datetime.now() - datetime.timedelta(days = 9))
I get the following results:
2016-06-03 16:04:03.706615
2016-06-03 15:49:03.706622
2016-06-03 15:49:03.706642
5:00:00
2016-06-06 16:04:03.706665
2016-05-25 16:04:03.706676
2016-05-25 16:04:03.706687
2016-06-03
16:04:03.706716
import datetime
datetime.datetime.now() - datetime.timedelta(0, 900)
Actually 900 is in seconds. Which is equal to 15 minutes. `15*60 = 900`
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