How to create a char[] using data from a boolean array?

Question

I have a Boolean array and I am trying to make a corresponding char array, so that to each true in the new array corresponds a 1 and for each false a 0. this is my code but it seems the new array is empty, because nothing prints, the Boolean nums[] prints fine.

char[] digits = new char[n];
for (int i = 0; i < n; i++) {
    if (nums[i]) {
        digits[i] = 1;
    }
    else if (!nums[i]) {
        digits[i] = 0;
    }
}
for (int k = 0; k < n; k++) {
    System.out.print (digits[k]);
}

Answer 1

Your problem is that you don't have quotes surrounding the 1 and 0.

for (int i = 0; i < n; i++) {
    if (nums[i]) {
        digits[i] = '1';
    }
    else {
        digits[i] = '0';
    }
}

Without the quotes, they are cast from ints to chars. 0 is actually the null character (NUL), and 1 is start of heading or something like that. Java chars are encoded using UTF-16 (they're 16 bits long). The characters '0' and '1' are actually encoded by 48 and 49 respectively (in decimal).

EDIT: Actually, don't look at the ASCII table, look at the Unicode character set. Unicode is really a superset of ASCII, but it'll probably be more useful than the ascii table