How to count digits, letters, spaces for a string in Python?

Question

I am trying to make a function to detect how many digits, letter, spaces, and others for a string.

Here's what I have so far:

def count(x):     length = len(x)     digit = 0     letters = 0     space = 0     other = 0     for i in x:         if x[i].isalpha():             letters += 1         elif x[i].isnumeric():             digit += 1         elif x[i].isspace():             space += 1         else:             other += 1     return number,word,space,other 

But it's not working:

>>> count(asdfkasdflasdfl222) Traceback (most recent call last):   File "<pyshell#4>", line 1, in <module>     count(asdfkasdflasdfl222) NameError: name 'asdfkasdflasdfl222' is not defined 

What's wrong with my code and how can I improve it to a more simple and precise solution?

Answer 1

Here's another option:

s = 'some string'  numbers = sum(c.isdigit() for c in s) letters = sum(c.isalpha() for c in s) spaces  = sum(c.isspace() for c in s) others  = len(s) - numbers - letters - spaces 

Answer 2

Following code replaces any nun-numeric character with '', allowing you to count number of such characters with function len.

import re len(re.sub("[^0-9]", "", my_string)) 

Alphabetical:

import re len(re.sub("[^a-zA-Z]", "", my_string)) 

More info - https://docs.python.org/3/library/re.html