I have the following pointer:
jfloat *verticesLocal;
And I want make a new copy to:
jfloat *vertices;
I want to copy the values from verticesLocal
to vertices
.
How can I do that? I've just tried the following command, but it doesn't work:
memcpy(vertices, verticesLocal, numVerticesLocal * sizeof(jfloat));
I can't see the error because I'm working with Android native code. Sorry.
Copying a pointer does not copy the corresponding object, leading to surprises if two pointers inadvertently points to the same object. Destroying a pointer does not destroy its object, leading to memory leaks.
You can assign 0 into a pointer: ptr = 0; The null pointer is the only integer literal that may be assigned to a pointer.
A pointer is associated with a type (of the value it points to), which is specified during declaration. A pointer can only hold an address of the declared type; it cannot hold an address of a different type.
The idea of "copying a pointer", when taken literally, is nothing more than a simple assignment.
int x = 5; int* p1 = &x; int* p2 = p1; // there, we copied the pointer.
In this case, both p1
and p2
point to the same data - the int
variable x
. However, because this is so trivial, I'm inclined to think that what you really are asking about is how to copy the data that the pointer points to.
In this case, it depends on the data type. If the pointer points to a simple buffer of PODs, this involves allocating a separate buffer, and then using something like memcpy
(or preferably std::copy
) to copy the data. For example:
int* p1 = new int[100]; // ... fill p1 with values int* p2 = new int[100]; // create a new buffer std::copy(p1, p1 + 100, p2); // copy the data into p2
Or, you can use memcpy
to copy the buffer byte-by-byte, since the buffer contains PODs.
memcpy(p2, p1, 100 * sizeof(int));
However, if the pointed-to data is not a simple buffer, but rather a C++ object, you can't use memcpy
. You need to perform a deep copy of the object, (usually using the object's copy constructor) to get a clone of the object. How this is done, or whether it's even possible, depends on the object. (Some objects are noncopyable.)
I have no clue what a jfloat
is, but if the object is, for example, an std::string
, you would just do something like:
std::string* s1; // assume this points to a valid string std::string* s2 = new std::string(); *s2 = *s1; // copies s1 using s2's assignment operator
In this contrived example it would be preferable to avoid heap-allocation altogether, and just use stack variables. But it demonstrates the idea of copying a heap-allocated object.
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