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How to copy tables avoiding cursors in SQL?

I want to write script in SQL that will copy these 2 tables(A,B) to other 2 tables(C,D) with the same structure as A,B accordingly.

IMPORTANT:

  1. Tables C,D are NOT necessary empty
  2. Several processes may call script simultaneously

Table A has foreign key(fk_a_b) of table B

   ________________________  _________________
   |        Table A       |  |   Table B     |  
   |______________________|  |_______________|
   | id     FK_A_B   name |  | id    visible |
   | ----- -------- ------|  | ----- --------|
   | 1      21       n1   |  | 21     true   |
   | 5      32       n2   |  | 32     false  |
   ------------------------  -----------------

Let say that after copying table B to D this is what I get

   ________________
   |   Table D    |  
   |______________|
   | id   visible |
   | ----- -------|
   | 51    true   |
   | 52    false  |
   ----------------

Now, when I'll copy table A to C I need to know, somehow, that ID=21 maps now to ID=51, and ID=32 to ID=52. Finally, the table C will be:

   ________________________
   |        Table C       |
   |______________________|
   | id     FK_C_D   name |
   | ----- -------- ------|
   | 61      51       n1  |
   | 62      52       n2  |
   ------------------------

Because several processes may call script simultaneously, I CAN'T alter table A,B to add some helper columns. So, to achieve this I used CURSOR. I copied row by row of table B and managed temp table to map OldId to NewId(21->51,32->52) and then used this temp table to copy table A.

I've read that CURSOR is bad practice. So, is there another way to do it?

Thank you

like image 615
theateist Avatar asked May 30 '11 09:05

theateist


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1 Answers

You can use the output clause with the merge statement to get a mapping between source id and target id. Described in this question. Using merge..output to get mapping between source.id and target.id

Here is some code that you can test. I use table variables instead of real tables.

Setup sample data:

-- @A and @B is the source tables
declare @A as table
(
  id int,
  FK_A_B int,
  name varchar(10)
)

declare @B as table
(
  id int,
  visible bit
)  

-- Sample data in @A and @B
insert into @B values (21, 1),(32, 0)
insert into @A values (1, 21, 'n1'),(5, 32, 'n2')


-- @C and @D is the target tables with id as identity columns
declare @C as table
(
  id int identity,
  FK_C_D int not null,
  name varchar(10)
)

declare @D as table
(
  id int identity,
  visible bit
)  

-- Sample data already in @C and @D
insert into @D values (1),(0)
insert into @C values (1, 'x1'),(1, 'x2'),(2, 'x3')

Copy data:

-- The @IdMap is a table that holds the mapping between
-- the @B.id and @D.id (@D.id is an identity column)
declare @IdMap table(TargetID int, SourceID int)

-- Merge from @B to @D.
merge @D as D             -- Target table
using @B as B             -- Source table
on 0=1                    -- 0=1 means that there are no matches for merge
when not matched then
  insert (visible) values(visible)    -- Insert to @D
output inserted.id, B.id into @IdMap; -- Capture the newly created inserted.id and
                                      -- map that to the source (@B.id)

-- Add rows to @C from @A with a join to
-- @IdMap to get the new id for the FK relation
insert into @C(FK_C_D, name)
select I.TargetID, A.name 
from @A as A
  inner join @IdMap as I
    on A.FK_A_B = I.SourceID

Result:

select *
from @D as D
  inner join @C as C
    on D.id = C.FK_C_D

id          visible id          FK_C_D      name
----------- ------- ----------- ----------- ----------
1           1       1           1           x1
1           1       2           1           x2
2           0       3           2           x3
3           1       4           3           n1
4           0       5           4           n2

You can test the code here: https://data.stackexchange.com/stackoverflow/q/101643/using-merge-to-map-source-id-to-target-id

like image 67
Mikael Eriksson Avatar answered Oct 04 '22 10:10

Mikael Eriksson