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How to convert Y-m-d H:i:s to Y-m-d in PHP?
I have e.g.
$date = "2011-08-10 20:40:12";
and would like to convert it to just
$output = "2011-08-10";
Thanks in advance.
304
Change YYYY-MM-DD to DD-MM-YYYY In the below example, we have date 2019-09-15 in YYYY-MM-DD format, and we will convert this to 15-09-2019 in DD-MM-YYYY format. $orgDate = "2019-09-15"; $newDate = date("d-m-Y", strtotime($orgDate)); echo "New date format is: ".
date_default_timezone_set('UTC'); echo "<strong>Display current date dd/mm/yyyy format </strong>". "<br />"; echo date("d/m/Y"). "<br />"; echo "<strong>Display current date mm/dd/yyyy format</strong> "."<br />"; echo date("m/d/Y")."<br />"; echo "<strong>Display current date mm-dd-yyyy format </strong>".
c - The ISO-8601 date (e.g. 2013-05-05T16:34:42+00:00) r - The RFC 2822 formatted date (e.g. Fri, 12 Apr 2013 12:01:05 +0200) U - The seconds since the Unix Epoch (January 1 1970 00:00:00 GMT)
Definition and Usage The strtotime() function parses an English textual datetime into a Unix timestamp (the number of seconds since January 1 1970 00:00:00 GMT). Note: If the year is specified in a two-digit format, values between 0-69 are mapped to 2000-2069 and values between 70-100 are mapped to 1970-2000.
quick/dirty:
$output = substr('2011-08-10 20:40:12', 0, 10);
slightly more robust:
$output = date('Y-m-d', strtotime('2011-08-10 20:40:12'));
fairly reliable:
$output = DateTime::createFromFormat('Y-m-d h:i:s', '2011-08-10-20:40:12')->format('Y-m-d');
Easily done with strtotime(), and capable of changing to any other date format you may need as well.
$old_date = "2011-08-10 20:40:12";
$new_date = date("Y-m-d", strtotime($old_date));
echo $new_date;
// Prints 2011-08-10
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