How to convert unicode string into normal text in python

Question

Consider I have a Unicode string (Not the real unicode but the string that looks like unicode). and I want to get it's utf-8 variant. How can I do it in Python? For example If I have String like:

title = "\\u10d8\\u10e1\\u10e0\\u10d0\\u10d4\\u10da\\u10d8 == \\u10d8\\u10d4\\u10e0\\u10e3\\u10e1\\u10d0\\u10da\\u10d8\\u10db\\u10d8"

How Can I do it so that I get its utf-8 variant (Georgian symbols):

ისრაელი == იერუსალიმი

To say it simply I want to Have code like:

title = "\\u10d8\\u10e1\\u10e0\\u10d0\\u10d4\\u10da\\u10d8 == \\u10d8\\u10d4\\u10e0\\u10e3\\u10e1\\u10d0\\u10da\\u10d8\\u10db\\u10d8"
utfTitle = title.TurnToUTF()
print(utfTitle)

And I want this code to have output:

ისრაელი == იერუსალიმი

Answer 1

You can use the unicode-escape codec to get rid of the doubled-backslashes and use the string effectively.

Assuming that title is a str, you will need to encode the string first before decoding back to unicode(str).

>>> t = title.encode('utf-8').decode('unicode-escape')
>>> t
'ისრაელი == იერუსალიმი'

If title is a bytes instance you can decode directly:

>>> t = title.decode('unicode-escape')
>>> t
'ისრაელი == იერუსალიმი'

Answer 2

Here, you go. Just use decode method and apply unicode_escape

For Python 2.x

title = "\\u10d8\\u10e1\\u10e0\\u10d0\\u10d4\\u10da\\u10d8 == \\u10d8\\u10d4\\u10e0\\u10e3\\u10e1\\u10d0\\u10da\\u10d8\\u10db\\u10d8"
utfTitle = title.decode('unicode_escape')
print(utfTitle)

#output :ისრაელი == იერუსალიმი

For python 3.x

title = "\\u10d8\\u10e1\\u10e0\\u10d0\\u10d4\\u10da\\u10d8 == \\u10d8\\u10d4\\u10e0\\u10e3\\u10e1\\u10d0\\u10da\\u10d8\\u10db\\u10d8"
print(title.encode('ascii').decode('unicode-escape'))