How to convert UInt8 byte array to string in Swift

Question

I am facing problems while converting UInt8 Byte array to string in swift. I have searched and find a simple solution

String.stringWithBytes(buff, encoding: NSUTF8StringEncoding) 

but it is showing error String.type does not have a member stringWithBytes. Can anyone suggest me a solution ?

this is my code where i am getting anNSData and converted into bytes array and then i have to convert that byte array into string.

let count = data.length / sizeof(UInt8) var array = [UInt8](count: count, repeatedValue: 0) data.getBytes(&array, length:count * sizeof(UInt8)) String.stringWithBytes(buff, encoding: NSUTF8StringEncoding) 

Answer 1

Update for Swift 3/Xcode 8:

String from bytes: [UInt8]:

if let string = String(bytes: bytes, encoding: .utf8) {     print(string) } else {     print("not a valid UTF-8 sequence") } 

String from data: Data:

let data: Data = ... if let string = String(data: data, encoding: .utf8) {     print(string) } else {     print("not a valid UTF-8 sequence") } 

---

Update for Swift 2/Xcode 7:

String from bytes: [UInt8]:

if let string = String(bytes: bytes, encoding: NSUTF8StringEncoding) {     print(string) } else {     print("not a valid UTF-8 sequence") } 

String from data: NSData:

let data: NSData = ... if let str = String(data: data, encoding: NSUTF8StringEncoding) {     print(str) } else {     print("not a valid UTF-8 sequence") } 

---

Previous answer:

String does not have a stringWithBytes() method. NSString has a

 NSString(bytes: , length: , encoding: ) 

method which you could use, but you can create the string directly from NSData, without the need for an UInt8 array:

if let str = NSString(data: data, encoding: NSUTF8StringEncoding) as? String {     println(str) } else {     println("not a valid UTF-8 sequence") } 

Answer 2

Swifty solution

array.reduce("", combine: { $0 + String(format: "%c", $1)}) 

Hex representation:

array.reduce("", combine: { $0 + String(format: "%02x", $1)})