I have a list like this:
paths = [['test_data', 'new_directory', 'ok.txt'], ['test_data', 'reads_1.fq'], ['test_data', 'test_ref.fa']]
I want to convert this into dictionary like this:
{'test_data': ['ok.txt', 'reads_1.fq'], 'test_data/new_directory', ['ok.txt']}
The list is dynamic. The purpose of this is to create a simple tree structure. I want to do this using itertools like this:
from itertools import izip
i = iter(a)
b = dict(izip(i, i))
Is something like this possible? Thanks
can try this also,
list1=['a','b','c','d']
list2=[1,2,3,4]
we want to zip these two lists and create a dictionary dict_list
dict_list = zip(list1, list2)
dict(dict_list)
this will give:
dict_list = {'a':1, 'b':2, 'c':3, 'd':4 }
Yes it is possible, use collections.defaultdict
:
>>> from collections import defaultdict
>>> dic = defaultdict(list)
>>> lis = [['test_data', 'new_directory', 'ok.txt'], ['test_data', 'reads_1.fq'],
for item in lis:
key = "/".join(item[:-1])
dic[key].append(item[-1])
...
>>> dic
defaultdict(<type 'list'>,
{'test_data': ['reads_1.fq', 'test_ref.fa'],
'test_data/new_directory': ['ok.txt']})
using simple dict
:
>>> dic = {}
>>> for item in lis:
key = "/".join(item[:-1])
dic.setdefault(key, []).append(item[-1])
...
>>> dic
{'test_data': ['reads_1.fq', 'test_ref.fa'],
'test_data/new_directory': ['ok.txt']}
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