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How to convert RGB camera image to ARGB format of SharpDX? [closed]

Tags:

c#

rgb

argb

I have a RGB image (RGB 4:4:4 colorspace, 24-bit per pixel), captured from camera. I use Gorgon 2D library (build base on SharpDX) to display this image as a texture so i have to convert it to ARGB. I use this code (not my code) to convert from RGB camera image to RGBA.

[StructLayout(LayoutKind.Sequential)]
public struct RGBA
{
            public byte r;
            public byte g;
            public byte b;
            public byte a;
}

[StructLayout(LayoutKind.Sequential)]
public struct RGB
{
            public byte r;
            public byte g;
            public byte b;
}

unsafe void internalCvt(long pixelCount, byte* rgbP, byte* rgbaP)
            {
                for (long i = 0, offsetRgb = 0; i < pixelCount; i += 4, offsetRgb += 12)
                {
                    uint c1 = *(uint*)(rgbP + offsetRgb);
                    uint c2 = *(uint*)(rgbP + offsetRgb + 3);
                    uint c3 = *(uint*)(rgbP + offsetRgb + 6);
                    uint c4 = *(uint*)(rgbP + offsetRgb + 9);
                    ((uint*)rgbaP)[i] = c1 | 0xff000000;
                    ((uint*)rgbaP)[i + 1] = c2 | 0xff000000;
                    ((uint*)rgbaP)[i + 2] = c3 | 0xff000000;
                    ((uint*)rgbaP)[i + 3] = c4 | 0xff000000;
                }
            }

public unsafe void RGB2RGBA(int pixelCount, byte[] rgbData, byte[] rgbaData)
            {
                if ((pixelCount & 3) != 0) throw new ArgumentException();
                fixed (byte* rgbP = &rgbData[0], rgbaP = &rgbaData[0])
                {
                    internalCvt(pixelCount, rgbP, rgbaP);
                }
            }

Then convert RGB to RGBA like this:

byte[] rgb = new byte[800*600*3]; //Stored data
byte[] rgba = new byte[800 * 600 * 4];
RGB2RGBA(800*600, rgb, rgba)

And I use rgba as data of Gorgon texture:

unsafe
{
     fixed(void* rgbaPtr = rgba)
     {
          var buff = new GorgonNativeBuffer<byte>(rgbaPtr, 800*600*4);                      
          GorgonImageBuffer imb = new GorgonImageBuffer(buff, 800, 600, BufferFormat.R8G8B8A8_UNorm);

          //Set Texture data  GorgonTexture2D                                
          Texture.SetData(imb, new SharpDX.Rectangle(0, 0, 800, 600), 0, 0, CopyMode.NoOverwrite);
         }
}

But the color of texture image is not like the color of camera image.

enter image description here

so I think I have to convert camera image to ARGB, (not RGBA) so that it can display with Gorgon texture but i dont know how to do it with the code above. Can you guys please point me some hints?

Thanks!

Below are the links to types of Gorgon Library i used in the code above

GorgonTexture2D GorgonNativeBuffer GorgonImageBuffer

like image 597
Dominota Avatar asked Aug 23 '19 06:08

Dominota


1 Answers

The byte order of the target is, in memory, R G B A. The byte order of the source is, in memory, B G R. So in addition to expanding every 3 bytes to 4 bytes and putting FF in the new A channel, the R and B channel need to swap position. For example,

unsafe void internalCvt(long pixelCount, byte* rgbP, uint* rgbaP)
{
    for (long i = 0, offsetRgb = 0; i < pixelCount; i += 4, offsetRgb += 12)
    {
        uint c1 = *(uint*)(rgbP + offsetRgb);
        uint c2 = *(uint*)(rgbP + offsetRgb + 3);
        uint c3 = *(uint*)(rgbP + offsetRgb + 6);
        uint c4 = *(uint*)(rgbP + offsetRgb + 9);
        // swap R and B
        c1 = (c1 << 16) | (c1 & 0xFF00) | ((c1 >> 16) & 0xFF);
        c2 = (c2 << 16) | (c2 & 0xFF00) | ((c2 >> 16) & 0xFF);
        c3 = (c3 << 16) | (c3 & 0xFF00) | ((c3 >> 16) & 0xFF);
        c4 = (c4 << 16) | (c4 & 0xFF00) | ((c4 >> 16) & 0xFF);
        // set alpha to FF
        rgbaP[i] = c1 | 0xff000000;
        rgbaP[i + 1] = c2 | 0xff000000;
        rgbaP[i + 2] = c3 | 0xff000000;
        rgbaP[i + 3] = c4 | 0xff000000;
    }
}

Or a simpler version that processes one pixel per iteration and doesn't use unsafe,

void internalCvt(long pixelCount, byte[] bgr, byte[] rgba)
{
    long byteCount = pixelCount * 4;
    for (long i = 0, offsetBgr = 0; i < byteCount; i += 4, offsetRgb += 3)
    {
        // R
        rgba[i] = bgr[offsetBgr + 2];
        // G
        rgba[i + 1] = bgr[offsetBgr + 1];
        // B
        rgba[i + 2] = bgr[offsetBgr];
        // A
        rgba[i + 3] = 0xFF;
    }
}
like image 142
harold Avatar answered Nov 20 '22 11:11

harold