I am on the stage of development, where I have two modules and from one I got output as a OutputStream
and second one, which accepts only InputStream
. Do you know how to convert OutputStream
to InputStream
(not vice versa, I mean really this way) that I will be able to connect these two parts?
Thanks
transferTo() Method. In Java 9 or higher, you can use the InputStream. transferTo() method to copy data from InputStream to OutputStream . This method reads all bytes from this input stream and writes the bytes to the given output stream in the original order.
We can convert a String to an InputStream object by using the ByteArrayInputStream class. This class constructor takes the string byte array which can be done by calling the getBytes() method of a String class.
The InputStream is used to read data from a source and the OutputStream is used for writing data to a destination.
There seem to be many links and other such stuff, but no actual code using pipes. The advantage of using java.io.PipedInputStream
and java.io.PipedOutputStream
is that there is no additional consumption of memory. ByteArrayOutputStream.toByteArray()
returns a copy of the original buffer, so that means that whatever you have in memory, you now have two copies of it. Then writing to an InputStream
means you now have three copies of the data.
The code:
// take the copy of the stream and re-write it to an InputStream PipedInputStream in = new PipedInputStream(); final PipedOutputStream out = new PipedOutputStream(in); new Thread(new Runnable() { public void run () { try { // write the original OutputStream to the PipedOutputStream // note that in order for the below method to work, you need // to ensure that the data has finished writing to the // ByteArrayOutputStream originalByteArrayOutputStream.writeTo(out); } catch (IOException e) { // logging and exception handling should go here } finally { // close the PipedOutputStream here because we're done writing data // once this thread has completed its run if (out != null) { // close the PipedOutputStream cleanly out.close(); } } } }).start();
This code assumes that the originalByteArrayOutputStream
is a ByteArrayOutputStream
as it is usually the only usable output stream, unless you're writing to a file. I hope this helps! The great thing about this is that since it's in a separate thread, it also is working in parallel, so whatever is consuming your input stream will be streaming out of your old output stream too. That is beneficial because the buffer can remain smaller and you'll have less latency and less memory usage.
An OutputStream
is one where you write data to. If some module exposes an OutputStream
, the expectation is that there is something reading at the other end.
Something that exposes an InputStream
, on the other hand, is indicating that you will need to listen to this stream, and there will be data that you can read.
So it is possible to connect an InputStream
to an OutputStream
InputStream----read---> intermediateBytes[n] ----write----> OutputStream
As someone metioned, this is what the copy()
method from IOUtils lets you do. It does not make sense to go the other way... hopefully this makes some sense
UPDATE:
Of course the more I think of this, the more I can see how this actually would be a requirement. I know some of the comments mentioned Piped
input/ouput streams, but there is another possibility.
If the output stream that is exposed is a ByteArrayOutputStream
, then you can always get the full contents by calling the toByteArray()
method. Then you can create an input stream wrapper by using the ByteArrayInputStream
sub-class. These two are pseudo-streams, they both basically just wrap an array of bytes. Using the streams this way, therefore, is technically possible, but to me it is still very strange...
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