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How to convert numpy datetime64 into datetime [duplicate]

I basically face the same problem posted here:Converting between datetime, Timestamp and datetime64

but I couldn't find satisfying answer from it, my question how to extract datetime from numpy.datetime64 type:

if I try:

np.datetime64('2012-06-18T02:00:05.453000000-0400').astype(datetime.datetime)

it gave me: 1339999205453000000L

my current solution is convert datetime64 into a string and then turn to datetime again. but it seems quite a silly method.

like image 214
user6396 Avatar asked Apr 20 '15 16:04

user6396


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2 Answers

Borrowing from Converting between datetime, Timestamp and datetime64

In [220]: x
Out[220]: numpy.datetime64('2012-06-17T23:00:05.453000000-0700')

In [221]: datetime.datetime.utcfromtimestamp(x.tolist()/1e9)
Out[221]: datetime.datetime(2012, 6, 18, 6, 0, 5, 452999)

Accounting for timezones I think that's right. Looks rather clunky though.

Using int() is more explicit (I think) than tolist()):

In [294]: datetime.datetime.utcfromtimestamp(int(x)/1e9)
Out[294]: datetime.datetime(2012, 6, 18, 6, 0, 5, 452999)

or to get datetime in local:

In [295]: datetime.datetime.fromtimestamp(x.astype('O')/1e9)

But in the test_datatime.py file https://github.com/numpy/numpy/blob/master/numpy/core/tests/test_datetime.py

I find some other options - first convert the general datetime64 to one of the format that specifies units:

In [296]: x.astype('M8[D]').astype('O')
Out[296]: datetime.date(2012, 6, 18)

In [297]: x.astype('M8[ms]').astype('O')
Out[297]: datetime.datetime(2012, 6, 18, 6, 0, 5, 453000)

This works for arrays:

In [303]: np.array([[x,x],[x,x]],dtype='M8[ms]').astype('O')[0,1]
Out[303]: datetime.datetime(2012, 6, 18, 6, 0, 5, 453000)
like image 131
hpaulj Avatar answered Oct 13 '22 00:10

hpaulj


Note that Timestamp IS a sub-class of datetime.datetime so the [4] will generally work

In [4]: pd.Timestamp(np.datetime64('2012-06-18T02:00:05.453000000-0400'))
Out[4]: Timestamp('2012-06-18 06:00:05.453000')

In [5]: pd.Timestamp(np.datetime64('2012-06-18T02:00:05.453000000-0400')).to_pydatetime()
Out[5]: datetime.datetime(2012, 6, 18, 6, 0, 5, 453000)
like image 35
Jeff Avatar answered Oct 12 '22 22:10

Jeff