How to convert InputStream to InputSource?

Question

ALL,

I wrote a simple SAX XML parser. It works and I was testing it with local XML file. Here is my code:

SAXParserFactory spf = SAXParserFactory.newInstance();
XMLParser xmlparser = null;
try
{
    SAXParser parser = spf.newSAXParser();
    XMLReader reader = parser.getXMLReader();
    xmlparser = new XMLParser();
    reader.setContentHandler( xmlparser );
    reader.parse( new InputSource( getResources().openRawResource( R.raw.categories ) ) );

Now I need to read this XML file from the website. The code I'm trying is:

public InputStream getXMLFile()
{
    URL url = new URL("http://example.com/test.php?param=0");
    InputStream stream = url.openStream();
    Document doc = docBuilder.parse(stream);
}
reader.parse( new Communicator().getXMLFile() );

I'm getting compiler error

"The method parse(InputSource) is not applicable for the argument (InputStream)".

I need help figuring out what do I need.

Thank you.

Answer 1

While I hate to sound obvious, is there any reason you're not using this constructor?

InputSource source = new InputSource(stream);
Document doc = docBuilder.parse(source);

Note that that's very similar to what you're doing in the first section of code. After all, openRawResource returns an InputStream as well...