A float value can be converted to an int value no larger than the input by using the math. floor() function, whereas it can also be converted to an int value which is the smallest integer greater than the input using math. ceil() function.
So you cannot store a float value in an int object through simple assignment. You can store the bit pattern for a floating-point value in an int object if the int is at least as wide as the float , either by using memcpy or some kind of casting gymnastics (as other answers have shown).
round() method, which converts float to its nearest integer by adding +0.5 to it's value and then truncating it.
How does the int function convert a float to an int? By rounding to the nearest whole number.
Using Math.round()
will round the float to the nearest integer.
Actually, there are different ways to downcast float to int, depending on the result you want to achieve:
(for int i
, float f
)
round (the closest integer to given float)
i = Math.round(f);
f = 2.0 -> i = 2 ; f = 2.22 -> i = 2 ; f = 2.68 -> i = 3
f = -2.0 -> i = -2 ; f = -2.22 -> i = -2 ; f = -2.68 -> i = -3
note: this is, by contract, equal to (int) Math.floor(f + 0.5f)
truncate (i.e. drop everything after the decimal dot)
i = (int) f;
f = 2.0 -> i = 2 ; f = 2.22 -> i = 2 ; f = 2.68 -> i = 2
f = -2.0 -> i = -2 ; f = -2.22 -> i = -2 ; f = -2.68 -> i = -2
ceil/floor (an integer always bigger/smaller than a given value if it has any fractional part)
i = (int) Math.ceil(f);
f = 2.0 -> i = 2 ; f = 2.22 -> i = 3 ; f = 2.68 -> i = 3
f = -2.0 -> i = -2 ; f = -2.22 -> i = -2 ; f = -2.68 -> i = -2
i = (int) Math.floor(f);
f = 2.0 -> i = 2 ; f = 2.22 -> i = 2 ; f = 2.68 -> i = 2
f = -2.0 -> i = -2 ; f = -2.22 -> i = -3 ; f = -2.68 -> i = -3
For rounding positive values, you can also just use (int)(f + 0.5)
, which works exactly as Math.Round
in those cases (as per doc).
You can also use Math.rint(f)
to do the rounding to the nearest even integer; it's arguably useful if you expect to deal with a lot of floats with fractional part strictly equal to .5 (note the possible IEEE rounding issues), and want to keep the average of the set in place; you'll introduce another bias, where even numbers will be more common than odd, though.
See
http://mindprod.com/jgloss/round.html
http://docs.oracle.com/javase/6/docs/api/java/lang/Math.html
for more information and some examples.
Math.round(value)
round the value to the nearest whole number.
Use
1) b=(int)(Math.round(a));
2) a=Math.round(a);
b=(int)a;
Math.round also returns an integer value, so you don't need to typecast.
int b = Math.round(float a);
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With