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I'm working on java... I want to know how to convert array of byte into BigInteger. Actually i used md5's digest method which returned me array of byte which i want to convert into Biginteger.
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BigInteger class provides operations for modular arithmetic, GCD calculation, primality testing, prime generation, bit manipulation, and a few other miscellaneous operations. BigInteger bInteger = new BigInteger(arr); The following is an example that creates BigInteger from a byte array in Java.
BigInteger: int bitCount +4 bytes int bitLength +4 bytes int firstNonzeroIntNum +4 bytes int lowestSetBit +4 bytes int signum +4 bytes int[] mag +? That's a total of 20 bytes + the integer array.
A big integer is a binary integer that occupies 8 bytes. The range of big integers is -9223372036854775808 to +9223372036854775807.
The BigInteger class has a longValue() method to convert a byte array to a long value: long value = new BigInteger(bytes). longValue();
This example Get MD5 hash in a few lines of Java has a related example.
I believe you should be able to do
MessageDigest m=MessageDigest.getInstance("MD5");
m.update(message.getBytes(), 0, message.length());
BigInteger bi = new BigInteger(1,m.digest());
and if you want it printed in the style "d41d8cd98f00b204e9800998ecf8427e" you should be able to do
System.out.println(bi.toString(16));
Actually i used md5's digest method which returned me array of byte which i want to convert into a
BigInteger.
You can use new BigInteger(byte[]).
However, it should be noted that the MD5 hash is not really an integer in any useful sense. It is really just a binary bit pattern.
I guess you are just doing this so that you can print or order the MD5 hashes. But there are less memory hungry ways of accomplishing both tasks.
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