How to convert an Int to a Character in Swift

Question

I've struggled and failed for over ten minutes here and I give in. I need to convert an Int to a Character in Swift and cannot solve it.

Question

How do you convert (cast) an Int (integer) to a Character (char) in Swift?

Illustrative Problem/Task Challenge

Generate a for loop which prints the letters 'A' through 'Z', e.g. something like this:

    for(var i:Int=0;i<26;i++) {      //Important to note - I know          print(Character('A' + i));   //this is horrendous syntax...     }                                //just trying to illustrate! :) 

Answer 1

You can't convert an integer directly to a Character instance, but you can go from integer to UnicodeScalar to Character and back again:

let startingValue = Int(("A" as UnicodeScalar).value) // 65 for i in 0 ..< 26 {     print(Character(UnicodeScalar(i + startingValue))) } 

Answer 2

How to convert an Int to a Character in Swift

For the sake of future visitors, I am providing a basic answer to the question title rather than the details of the question itself.

It is a two step process. Convert the Int to a UnicodeScalar and then convert the UnicodeScalar to a Character.

let myInteger: Int = 97  // convert Int to a valid UnicodeScalar guard let myUnicodeScalar = UnicodeScalar(myInteger) else {     return }  // convert UnicodeScalar to Character let myCharacter = Character(myUnicodeScalar)  // results print(myCharacter) // a 

(source)

Or alternatively...

if let myUnicodeScalar = UnicodeScalar(97)      let myCharacter = Character(myUnicodeScalar) } 

See also

• How to express Strings in Swift using Unicode hexadecimal values (UTF-16)
• Working with Unicode code points in Swift