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How to convert a string (with leading zero or not) to an integer? For example, '08' to 8.
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To convert, or cast, a string to an integer in Python, you use the int() built-in function. The function takes in as a parameter the initial string you want to convert, and returns the integer equivalent of the value you passed. The general syntax looks something like this: int("str") .
The simplest approach to solve the problem is to traverse the string up to the first non-zero character present in the string and store the remaining string starting from that index as the answer. If the entire string is traversed, it means all the characters in the string are '0'.
The int() method to remove leading zeros in PythonThe first method is the int() method, which converts a string into an integer. While converting, it will automatically remove leading zeros in the string. Note that the string should only contain numbers and no letters, alphabets, or other symbols.
1) Console. WriteLine("false"); else Console. WriteLine("true"); if the string starts with '0' and if it has more than one character.
There are several ways to convert a string to a number, I prefer to use the unary + operator:
var number = +"08"; // 8
This is the equivalent of writing:
var number = Number("08"); // 8
Unlike parseInt(), when using + or Number() no radix is necessary because the internal number conversion will not parse octal numbers. If you want the parseInt() or parseFloat() methods, it's also pretty simple:
var number = parseInt("08", 10); // 8
parseInt and parseFloat are less reliable for user input because an invalid numeric literal might be considered salvageable by these functions and return an unexpected result. Consider the following:
parseInt("1,000"); // -> 1, not 1000
+"1,000"; // -> NaN, easier to detect when there's a problem
Extra Reading
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Use parseInt() with the radix argument. This disables autodetection of the base (leading 0 -> octal, leading 0x -> hex):
var number = parseInt('08', 10);
// number is now 8
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