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Is there a way to convert a float to an Int by rounding to the nearest possible whole integer?
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round() method, which converts float to its nearest integer by adding +0.5 to it's value and then truncating it.
Round() Round() is a built-in function available with python. It will return you a float number that will be rounded to the decimal places which are given as input. If the decimal places to be rounded are not specified, it is considered as 0, and it will round to the nearest integer.
Reference (thanks Rawling) Explicit Numeric Conversions Table: When you convert a double or float value to an integral type, this value is rounded towards zero to the nearest integral value.
To round to the nearest use roundf(), to round up use ceilf(), to round down use floorf(). Hopefully this example demonstrates...
#import "math.h" ... float numberToRound; int result; numberToRound = 4.51; result = (int)roundf(numberToRound); NSLog(@"roundf(%f) = %d", numberToRound, result); // roundf(4.510000) = 5 result = (int)ceilf(numberToRound); NSLog(@"ceilf(%f) = %d", numberToRound, result); // ceilf(4.510000) = 5 result = (int)floorf(numberToRound); NSLog(@"floorf(%f) = %d", numberToRound, result); // floorf(4.510000) = 4 numberToRound = 10.49; result = (int)roundf(numberToRound); NSLog(@"roundf(%f) = %d", numberToRound, result); // roundf(10.490000) = 10 result = (int)ceilf(numberToRound); NSLog(@"ceilf(%f) = %d", numberToRound, result); // ceilf(10.490000) = 11 result = (int)floorf(numberToRound); NSLog(@"floorf(%f) = %d", numberToRound, result); // floorf(10.490000) = 10 numberToRound = -2.49; result = (int)roundf(numberToRound); NSLog(@"roundf(%f) = %d", numberToRound, result); // roundf(-2.490000) = -2 result = (int)ceilf(numberToRound); NSLog(@"ceilf(%f) = %d", numberToRound, result); // ceilf(-2.490000) = -2 result = (int)floorf(numberToRound); NSLog(@"floorf(%f) = %d", numberToRound, result); // floorf(-2.490000) = -3 numberToRound = -3.51; result = (int)roundf(numberToRound); NSLog(@"roundf(%f) = %d", numberToRound, result); // roundf(-3.510000) = -4 result = (int)ceilf(numberToRound); NSLog(@"ceilf(%f) = %d", numberToRound, result); // ceilf(-3.510000) = -3 result = (int)floorf(numberToRound); NSLog(@"floorf(%f) = %d", numberToRound, result); // floorf(-3.510000) = -4 The documentation...
https://developer.apple.com/library/archive/documentation/System/Conceptual/ManPages_iPhoneOS/man3/roundf.3.html
https://developer.apple.com/library/archive/documentation/System/Conceptual/ManPages_iPhoneOS/man3/ceil.3.html
https://developer.apple.com/library/archive/documentation/System/Conceptual/ManPages_iPhoneOS/man3/floor.3.html
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