I am trying to convert a dictionary:
data_dict = {'t1': '1', 't2': '2', 't3': '3'}
into a dataframe:
key | value|
----------------
t1 1
t2 2
t3 3
To do that, I tried:
schema = StructType([StructField("key", StringType(), True), StructField("value", StringType(), True)])
ddf = spark.createDataFrame(data_dict, schema)
But I got the below error:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/local/Cellar/apache-spark/2.4.5/libexec/python/pyspark/sql/session.py", line 748, in createDataFrame
rdd, schema = self._createFromLocal(map(prepare, data), schema)
File "/usr/local/Cellar/apache-spark/2.4.5/libexec/python/pyspark/sql/session.py", line 413, in _createFromLocal
data = list(data)
File "/usr/local/Cellar/apache-spark/2.4.5/libexec/python/pyspark/sql/session.py", line 730, in prepare
verify_func(obj)
File "/usr/local/Cellar/apache-spark/2.4.5/libexec/python/pyspark/sql/types.py", line 1389, in verify
verify_value(obj)
File "/usr/local/Cellar/apache-spark/2.4.5/libexec/python/pyspark/sql/types.py", line 1377, in verify_struct
% (obj, type(obj))))
TypeError: StructType can not accept object 't1' in type <class 'str'>
So I tried this without specifying any schema but just the column datatypes:
ddf = spark.createDataFrame(data_dict, StringType()
& ddf = spark.createDataFrame(data_dict, StringType(), StringType())
But both result in a dataframe with one column which is key of the dictionary as below:
+-----+
|value|
+-----+
|t1 |
|t2 |
|t3 |
+-----+
Could anyone let me know how to convert a dictionary into a spark dataframe in PySpark ?
We can convert a dictionary to a pandas dataframe by using the pd. DataFrame. from_dict() class-method.
You can use data_dict.items()
to list key/value pairs:
spark.createDataFrame(data_dict.items()).show()
Which prints
+---+---+
| _1| _2|
+---+---+
| t1| 1|
| t2| 2|
| t3| 3|
+---+---+
Of course, you can specify your schema:
spark.createDataFrame(data_dict.items(),
schema=StructType(fields=[
StructField("key", StringType()),
StructField("value", StringType())])).show()
Resulting in
+---+-----+
|key|value|
+---+-----+
| t1| 1|
| t2| 2|
| t3| 3|
+---+-----+
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