How to compare floating point values in Scala?

Question

As far as I know, exact comparison doesn't make much sense with floating point values as what is intended to be 0.0001 can actually be something like 0.0001000...0001... Should I implement my own comparison function to specify precision or is there a common practice for this?

I used to use the following with C# (which, I suspect, is still wrong as a Double value can be probably uncapable of representing 0.0001 at all, even set as a constant (as Michael Borgwardt explained here)):

public static bool AlmostEquals(this double x, double y, double precision = 0.0001) {   if (precision < 0.0)     throw new ArgumentException();    return Math.Abs(x - y) <= precision; } 

Should I do something alike in Scala?

Answer 1

Yes, you can do the same thing as in Java. You could also use some of Scala's cool features and pimp the Double class with a ~= method that takes an implicit precision parameter that only needs to be specified once.

scala> case class Precision(val p:Double) defined class Precision  scala> class withAlmostEquals(d:Double) {   def ~=(d2:Double)(implicit p:Precision) = (d-d2).abs <= p.p } defined class withAlmostEquals  scala> implicit def add_~=(d:Double) = new withAlmostEquals(d) add_$tilde$eq: (d: Double)withAlmostEquals  scala> 0.0~=0.0 <console>:12: error: could not find implicit value for parameter p: Precision               0.0~=0.0                  ^  scala> implicit val precision = Precision(0.001) precision: Precision = Precision(0.001)  scala> 0.0 ~= 0.00001 res1: Boolean = true