I want to get the items which were created today with by a QueryBuilder from Doctrine2. I want to compare the createdAt(Datetime) field with today parameter(Date). Is it possible to do that in one query?
$qb = $this->createQueryBuilder('i');
$qb->innerJoin('i.type', 'it');
$qb->andWhere('it.name = :type');
$qb->andWhere('i.createdAt < :today');
// i.createdAt == datetime and :today parameter is a date
Compare() method in C# is used for comparison of two DateTime instances. It returns an integer value, <0 − If date1 is earlier than date2. 0 − If date1 is the same as date2.
Simply use the methods isAfter() , isBefore() or isAtSameMomentAs() from DateTime . Other alternative, use compareTo(DateTime other) , as in the docs: Compares this DateTime object to [other], returning zero if the values are equal.
It is also possible to use built-in function DATE_DIFF(date1, date2)
which returns difference in days. Check docs
$result = $this->createQueryBuilder('l')
->where('DATE_DIFF(l.startDate, CURRENT_DATE()) = 0')
one idea is to extract from the date: the year, month and day. And then
$qb->select('p')
->where('YEAR(p.postDate) = :year')
->andWhere('MONTH(p.postDate) = :month')
->andWhere('DAY(p.postDate) = :day');
$qb->setParameter('year', $year)
->setParameter('month', $month)
->setParameter('day', $day);
MONTH DAY, and YEAR you take out the DoctrineExtensions from
e.g.
DoctrineExtensions
This works for me. You only need the files: day.php, month.php and year.php.....
You get the month e.g.:
$datetime = new \DateTime("now");
$month = $datetime->format('m');
echo $month;
Copy day.php, month.php and year.php to your bundle Xy\TestBundle\Dql Register the new functions in app\config.yml with
doctrine:
orm:
auto_generate_proxy_classes: %kernel.debug%
entity_managers:
default:
auto_mapping: true
dql:
datetime_functions:
month: Xy\TestBundle\Dql\Month
year: Xy\TestBundle\Dql\Year
day: Xy\TestBundle\Dql\Day
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