So, I've searched high and low, and I can't find an answer to this. I've attempted it about three times and gotten a basic one cranked out by basically storing the input in an array as a string, parsing the numbers, then switching on the operator, in order to evaluate the integers, but I'm having a really hard time figuring out the chaining logic. Does anyone have any suggestions? Of maybe even just the psuedocode? I really don't want to use eval. Thanks a lot
const number1 = parseFloat(prompt ('Enter the first number: ')); const number2 = parseFloat(prompt ('Enter the second number: ')); let result; // declaration of the variable. // use if, elseif and else keyword to define the calculator condition in JavaScript.
An alternative to eval is Function() . Just like eval() , Function() takes some expression as a string for execution, except, rather than outputting the result directly, it returns an anonymous function to you that you can call.
Yes, it is doable, and you don't risk having to sell your heck out to be forgiven by the coding community. It's just that the use of an eval will not allow you to obtain a mastery of the calculation and will sometimes give you abhorrent results, as Binary indicates to you in its comment.
For a simple calculator with only 5 operators (^, *, /, +, -) and no parentheses, you can do something like this. First, it is convenient to turn the string into an array of numbers and operators. Then, we go through the array looking for each operator in order of precedence, and applying the operator to the numbers preceding and following the it.
function tokenize(s) {
// --- Parse a calculation string into an array of numbers and operators
const r = [];
let token = '';
for (const character of s) {
if ('^*/+-'.includes(character)) {
if (token === '' && character === '-') {
token = '-';
} else {
r.push(parseFloat(token), character);
token = '';
}
} else {
token += character;
}
}
if (token !== '') {
r.push(parseFloat(token));
}
return r;
}
function calculate(tokens) {
// --- Perform a calculation expressed as an array of operators and numbers
const operatorPrecedence = [{'^': (a, b) => Math.pow(a, b)},
{'*': (a, b) => a * b, '/': (a, b) => a / b},
{'+': (a, b) => a + b, '-': (a, b) => a - b}];
let operator;
for (const operators of operatorPrecedence) {
const newTokens = [];
for (const token of tokens) {
if (token in operators) {
operator = operators[token];
} else if (operator) {
newTokens[newTokens.length - 1] =
operator(newTokens[newTokens.length - 1], token);
operator = null;
} else {
newTokens.push(token);
}
}
tokens = newTokens;
}
if (tokens.length > 1) {
console.log('Error: unable to resolve calculation');
return tokens;
} else {
return tokens[0];
}
}
const userInput = document.getElementById('userInput');
userInput.focus();
userInput.addEventListener('input', function() {
document.getElementById('result').innerHTML = "The answer is " + calculate(tokenize(userInput.value));
});
<input type="text" id="userInput" />
<div id="result"></div>
(Alternative version here). To allow parentheses, you could tell the calculate
function to check for parentheses before it starts looking for any of the other operators, then recursively call itself on the expression within each set of parentheses. The parsing function can also be improved e.g. removing any white space and dealing with errors.
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